PLEASE HELP!!!! Solve 2/3x -1/5 > 1 x > ____
1 answer:
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Step-by-step explanation:
- 5+<em>4</em>=9
- 9+<em>5</em><em>=</em>14
- 14+<em>6</em><em>=</em>20
- 20+<em>7</em><em>=</em><u>2</u><u>7</u>
- 27+<em>8</em><em>=</em>35
So The sequence is 5,9,14,20,<u>2</u><u>7</u><u>,</u>35
Answer:
(a)Therefore the volume of the box is 361.19 cubic ft.
(b)Therefore the volume of the box is 361.19 cubic ft.
Step-by-step explanation:
Given that,
Squares with sides length x are cut out from of each corner of a rectangular piece of cardboard measuring 23 ft and 13 ft.
Now the length of the box is =(23-2x) ft
The width of the box is =(13-2x) ft
The height of the box is= x
The volume of the box is = Length×width×Height
=(23-2x)(13-2x)x cubic ft
= 299x-72x²+4x³ cubic ft
Let,
V=299x-72x²+4x³
Differentiating with respect to x
V'= 299-144x+12x²
Again differentiating with respect to x
V''= -144+24x
To find the maximum volume, we set V'=0
∴299-144x+12x²=0
Applying quadratic formula , here a=12,b= -144 and c=299
For x= 9.33 , the width of the box will negative which is impossible.
So, x= 2.67
So, at x=2.67, the volume of the box will be maximum.
Therefore the volume of the box is
=(299x-72x²+4x³) cubic ft
=361.19 cubic ft
(b)
The value of s will same with the value of x
so the volume of the box also remains same.
Therefore the volume of the box is 361.19 cubic ft
Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.
Step-by-step explanation:
Since we have given that
ΔPQS, and ΔSQR,
Consider, ΔPQS,
As we know that " the length opposite to the largest angle is the shortest segment."
So, According to the above statement.
Similarly,
Consider, ΔSQR,
Again applying the above statement, we get that,
Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.