Answer:
a
Step-by-step explanation:
All of the steps are good up until the 25-0, instead a 0 should have put into the top and the 1 brought down so that it was 251-248 which gets you 3 as a remainder so the answer is 804 R3
Answer:
Step-by-step explanation:
<h3>A.</h3>
The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>
The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
The base unit of volume is the cubic meter, there are 1000 liters per cubic meter
Answer:
259.6 ft/sec
Step-by-step explanation:
it is a universal standard that acceleration due to gravity is 32ft/sec^2.
Now it can be verified by equation,
V(f) = V(i)+at (1st equation of motion derived by Newton's three laws of motion)
where,
V(f) is final velocity
V(i) is initial velocity
a is acceleration which is constant and have value 32ft/sec^2
t is time which is given as 7.8 seconds
In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.
So,
V(f) = 0 +(32) (7.8)
V(f) = 249.6 ft/sec
Now the condition is given that you have to add a constant 10 to the answer.
so, V(f) = 249.6 + 10
V(f) = 259.6 ft/sec
