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horrorfan [7]
2 years ago
7

Answer for fee rbux and branlest!!!! i need answer NOW or i will be DIE (not good!!!)

Mathematics
1 answer:
pshichka [43]2 years ago
8 0

Answer:

its B homie

Step-by-step explanation:

U stuped

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What is the remainder of 2,445 ÷ 8
Kryger [21]
Answer:

305 Remainder 5
6 0
2 years ago
Simplify the problem 7x+4(6-x)+28
nignag [31]

Answer: 3

x

+

52


Step-by-step explanation:


8 0
2 years ago
What is the gcf of 12 78 and 90
Anuta_ua [19.1K]
The greatest common factor of 12, 78, and 90 is 6.

Factors are the numbers, that when multiplied with another number, equal the product.

Factors of 12: 1, 2, 3, 4, 6, and 12.
Factors of 78: 1, 2, 3, 6, 13, 26, 39, and 78.
Factors of 90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 20, 45, and 90.

The Greatest Common Factor is the highest factor shared among the products. Thus proving 6 is the GCF.

I hope this helps!
7 0
3 years ago
Expand and simplify 4(x-3)-2(x-1)
Nuetrik [128]

Answer:

-2 4x square is the answer

3 0
3 years ago
URGENT!!! What happens to the graph of y=−x6−6x5+50x3+45x2−108x−108 as x heads toward ∞ and −∞?
mr Goodwill [35]

Using limits, the correct option regarding the end behavior of the function is given by:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

<h3>How to find the end behavior of a function f(x)?</h3>

The end behavior is found calculating the limit of f(x) as x goes to infinity.

For this problem, the equation is given by:

f(x) = -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108

Since x goes to infinity, we consider only the term with the highest exponent, hence the limits are given as follows:

\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow -\infty} -x^6 = -(-\infty)^6 = -\infty

\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow \infty} -x^6 = -(\infty)^6 = -\infty

Hence the correct option is:

A. as x→∞, y→−∞ as x→−∞, y→−∞.

More can be learned about limits and end behavior at brainly.com/question/22026723

#SPJ1

3 0
1 year ago
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