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Afina-wow [57]
3 years ago
7

Hollis and Charmaine are curious about which mode of transportation gets them from their apartment to the mall faster. Hollis ta

kes public transportation and gets to the mall in 18.5 minutes. Charmaine rides her bike and gets to the mall in 0.5 hours. The mall is 2.4 miles away from their apartment
Mathematics
1 answer:
guapka [62]3 years ago
8 0
In order to assess which method of transportation is faster, we will look at the time they take, since the distance is the same for both. In order to compare the times, we must make the units that they are both measured in consistent. We must either convert 18.5 minutes into hour or 0.5 hour into minutes. We will go with the latter as it is easier:

0.5 hours = 0.5 hours x 60 minutes per hour = 30 minutes

Therefore, the public transport takes them to the mall faster, since it takes only 18.5 minutes, than cycling to the mall does, which takes 30 minutes.
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Answer the questions.
Paladinen [302]

Answer:

5.

Objective C

125x + 200 \geqslant 1200 \\ 125x  \geqslant  1000 \\ x  \geqslant 8

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x \:  \alpha  \: y \\ y = kx \\ 2.00 = k \times 8 \\ k =  \frac{2.00}{8}  \\ k = 0.25

3 0
2 years ago
Can someone walk me through this?
shepuryov [24]
I hope this helps you



Ax+By=C



By=C-Ax


y=C/B-A/Bx


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8 0
3 years ago
Lupita rides a taxi that charges a flat rate of $6.75 plus $3.20 per mile. If the taxi charges Lupita $40.03 in total for her tr
yaroslaw [1]

Answer:

10.4 miles

Step-by-step explanation:

Write an equation for the total cost paid as a function of the # of miles driven:

L(x) = $6.75 + ($3.20/mile)x

and set this equal to $40.03 to determine the # of miles Lupita rode:

L(x) = $6.75 + ($3.20/mile)x = $40.03

Isolate the x term by subtracting $6.75 from both sides:

($3.20/mile)x = $40.03 - $6.75 = $33.28

Finally, divide both sides by  ($3.20/mile):

x = $33.28 /  ($3.20/mile)

  =  10.4 miles

Lupita rode 10.4 miles in the taxi.

4 0
3 years ago
Increase £80 by 15%<br>​
Juliette [100K]
The answer to your question is 92
3 0
2 years ago
If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
seraphim [82]

Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

from (1)(2) => proven

5 0
3 years ago
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