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Phantasy [73]
3 years ago
13

Help ASAP only right answers only no spam don’t answer if you don’t know

Chemistry
1 answer:
ziro4ka [17]3 years ago
3 0

Answer:

element.... ....

.....

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4Cr(s)+3O2 (g )= Cr2O3 (s)<br> Find the theoretical yield in moles and grams
Assoli18 [71]
The balanced reaction is:

<span>4Cr(s)+3O2 (g )= Cr2O3 (s)

Since we are not given the amount of any of the reactants, we assume we have one gram of chromium. Calculations are as follows:

1 g Cr ( 1 mol Cr / 52 g Cr ) ( 1 mol Cr2O3 / 4 mol Cr ) = <span>0.005 mol Cr2O3

</span></span>0.005 mol Cr2O3 (151.99 g Cr2O3 / 1 mol Cr2O3 ) = 0.7307 g <span>Cr2O3
</span>
Therefore, the theoretical yield for 1 gram of Cr is 0.005 mol Cr2O3 or 0.7307 g Cr2O3.
7 0
3 years ago
Which of the following statements is true about atoms?
Leokris [45]

Atoms of the same element may have different mass numbers.

6 0
3 years ago
3)<br> How many atoms are in 14 moles of cadmium?
andre [41]

Answer:

8.4322\times10^{24} atoms atoms are in 14 moles of cadmium.

Explanation:

Cadmium is a white and  silvery  metal  that is found in the curst of the earth.During the  production process of metals such as lead, copper, zinc, cadmium is extracted

Cadmium is present in some foods and is emitted when fossil fuels like as coal and oil is used, smoking cigarettes. It is used in craft glazes, metal batteries, and coatings.

We know that 1 mole of  Cadmium (Cd contains) 6.023*1023 atoms, which is Avogadro's number.

So in 14 Grams of Cadmium, the number of atoms present is,

=>14×number atoms present in one cadmium atom

=>14\times 6.023\times10^{23}

=>8.4322\times10^{24} atoms

5 0
4 years ago
What does green design refer to?
prohojiy [21]

Answer:A

Explanation:APEX just told me the answer

4 0
4 years ago
In which laboratory process could a student use 0.10 M NaOH(aq) to determine the concentration of an aqueous solution of HBr?
telo118 [61]
(4) titration, the process of using an aqueous solution of known concentration to determine the concentration of another solution of unknown concentration, is your answer.
8 0
4 years ago
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