Question

In an electrical circuit 200mC of charge flows through a 50kohm resistor in 90 seconds. What is the power

Answer 1

Answer: $0.2464\ W$

Explanation:

Given

Charge $Q=200\ mC$

Resistance $R=50\ k\Omega$

Time $t=90\ s$

Charge is the amount of current flown in a particular time

$Q=It\\\Rightarrow 200\times 10^{-3}=I\times 90\\\\\Rightarrow I=\dfrac{200\times 10^{-3}}{90}\\\\\Rightarrow I=2.22\times 10^{-3}\ A$

Power is the given by $P=I^2R$

Insert values

$\Rightarrow P=\left(2.22\times 10^{-3}\right)^2\times 50\times 10^3\\\\\Rightarrow P=246.42\times 10^{-3}\ W\\\\\Rightarrow P=0.2464\ W$

The power is in the circuit is $0.2464\ W$.