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Solnce55 [7]
3 years ago
13

What is the equilibrium expression for the reaction below?

Chemistry
1 answer:
Delvig [45]3 years ago
3 0

Answer:

D. [CO₂]

Explanation:

Let's consider the following equation at equilibrium.

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients. It only includes gases and aqueous species.

Kc = [CO₂]

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Determine which of the acids are Arrhenius acids, Brønsted–Lowry acids, and Lewis acids. It is possible for an acid to be of mor
tatyana61 [14]

This is an incomplete question, here is a complete question.

Determine which of the acids are Arrhenius acids, Brønsted–Lowry acids, and Lewis acids. It is possible for an acid to be of more than one type. Which acids are Arrhenius acids?

AlCl₃ (aq)

BCl₃ (aq)

HCl (aq)

Answer :

HCl is an Arrhenius acid and Bronsted Lowry acid

AlCl₃ is a Lewis-acid

BCl₃ is a Lewis-acid

Explanation :

According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions (OH^-) when dissolved in water and an acid is defined as a substance which donates hydronium ions (H_3O^+) in water.

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

From this we conclude that:

HCl is an Arrhenius acid because it donates hydrogen ion and also Bronsted Lowry acid because it also donate protons.

AlCl₃ is a Lewis-acid because it is a electron deficient and accept lone pair of elections.

BCl₃ is a Lewis-acid because it is a electron deficient and accept lone pair of elections.

7 0
3 years ago
How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL o
Rama09 [41]

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

<u>Step 1: </u>Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

<u>Step 2:</u> The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

<u>Step 3:</u> Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH =  0.0075 moles

<u>Step 4</u>: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

<u>Step 5:</u> Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

7 0
3 years ago
A sample contains 16. 75 g of the radioisotope U-236 and 50. 25 g of its daughter isotope, Th-232. How long did it take for deca
garri49 [273]

The time taken for the isotope to decay is 46 million years.

We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

  • Original amount (N₀) = 50.25 g
  • Amount remaining (N) = 16.75
  • Number of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = N₀ / N

2ⁿ = 50.25 / 16.75

2ⁿ = 3

Take the log of both side

Log 2ⁿ = 3

nLog 2 = Log 3

Divide both side by log 2

n = Log 3 / Log 2

n = 2

Finally, we shall determine the time.

  • Half-life (t½) = 23 million years
  • Number of half-lives (n) = 2
  • Time (t) =?

t = n × t½

t = 2  × 23

t = 46 million years

Learn more about half-life: brainly.com/question/25927447

8 0
3 years ago
Read 2 more answers
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Chemical? Perhaps because it is changing?
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4 years ago
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what is Calcite's Solubility, I barely know what solubility mean let alone what it has to do with Calcite.
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Calcite can be either dissolved by groundwater or precipitated by groundwater, depending on several factors including the water temperature, pH, and dissolved ion concentrations. Although calcite is fairly insoluble in cold water, acidity can cause dissolution of calcite and release of carbon dioxide gas.

7 0
3 years ago
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