Question

A sample contains 16. 75 g of the radioisotope U-236 and 50. 25 g of its daughter isotope, Th-232. How long did it take for decay to take place if one half-life of U-236 is 23 million years? 46 million years 69 million years 92 million years 115 million years.

Answer 1

The time taken for the isotope to decay is 46 million years.

We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

• Original amount (N₀) = 50.25 g

• Amount remaining (N) = 16.75

• Number of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = N₀ / N

2ⁿ = 50.25 / 16.75

2ⁿ = 3

Take the log of both side

Log 2ⁿ = 3

nLog 2 = Log 3

Divide both side by log 2

n = Log 3 / Log 2

n = 2

Finally, we shall determine the time.

• Half-life (t½) = 23 million years

• Number of half-lives (n) = 2

• Time (t) =?

t = n × t½

t = 2  × 23

t = 46 million years

Learn more about half-life: brainly.com/question/25927447

Answer 2

Answer:

A.46 Million years

Explanation: