2.
2 answers:
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Answer:
the diameter of the second pipe is 2.52 in
Explanation:
Given the data in the question;
We know that; the rate of flow is the same;
so
Av1 = Av2
v ∝ √h
=
= √(
)
( π/4.D1² / π/4.D2² ) = √( )
( D1² / D2² ) = √( ) since second is double of first
so
( D1² / D2² ) = √( )
3² / D2² = √2
D2²√2 = 9
D2² = 9/√2
D2² = 9 / 1.4142
D2² = 6.364
D2 = √ 6.364
D2 = 2.52 in
Therefore, the diameter of the second pipe is 2.52 in