Answer:
Truck will be at a distance of 720 m
Explanation:
Speed of the truck is given as 90 m/sec
Time for which truck travel t = 10 seconds
We have to find the distance that how much truck travel in 8 sec with speed of 90 m/sec
We know that distance is given by 
So distance traveled by truck in 8 sec will be equal to 
So truck will be at a distance of 720 m
Answer:
R2= 470 ohms R1= 10ohms. Schematic is attached
Explanation:
Av=-(R2/R1)
-47=-(470/10)
-47=-47
The traditional forecast process employed by most NMHSs involves forecasters producing text-based, sensible, weather-element forecast products (e.g. maximum/minimum temperature, cloud cover) using numerical weather prediction (NWP) output as guidance. The process is typically schedule-driven, product-oriented and labour-intensive. Over the last decade, technological advances and scientific breakthroughs have allowed NMHSs’ hydrometeorological forecasts and warnings to become much more specific and accurate.
As computer technology and high-speed dissemination systems evolved (e.g. Internet), National Weather Service (NWS) customers/partners were demanding detailed forecasts in gridded, digital and graphic formats. Traditional NWS text forecast products limit the amount of additional information that can be conveyed to the user community. The concept of digital database forecasting provides the capability to meet customer/partner demands for more accurate, detailed hydrometeorological forecasts. Digital database forecasting also offers one of the most exciting opportunities to integrate PWS forecast dissemination and service delivery, which most effectively serves the user community.
Both the US National Oceanic and Atmospheric Administration(NOAA)/National Weather Service and Environment Canada are currently using digital database forecasting technology to produce routine forecasts. The Australian Bureau of Meteorology is in the process of evaluating and developing an implementation plan for database forecasting using the NOAA/NWS National Digital Forecast Database approach.
When two charged plates are separated by a distance, the potential difference between the plates is 54 Volts.
<h3>What is uniform electric field?</h3>
The electric field intensity which does not increase or decrease with time or remain constant is called the uniform electric field.
Given is the plates separated by distance d = 15 cm =0.15 m, electric field E= 360 N/C.
The relation between the electric field and voltage is
E=V/d
Substitute the values into the expression to get the potential difference V,
V = 360 x 0.15
V = 54 Volts
Thus, the potential difference between the plates is 54 Volts.
Learn more about uniform electric field.
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Responder:
Explicación:
Para que podamos calcular el tiempo que le tomará al esquiador permanecer en el aire, encontraremos el tiempo de vuelo como se muestra;
T = 2Usin theta / 2
theta = 90 grados
U = 25 m / s
T = 25sin90 / 2 (9,8)
T = 25 / 19,62
T = 1,27 segundos
Por lo tanto, los cielos usarán 1.27 segundos en el aire.
La distancia horizontal es el rango;
Rango R = U√2H / g
R = 25√2 (80) /9,8
R = 25√160 / 9,8
R = 25 * √16,326
R = 25 * 4.04
R = 101,02 m
Por tanto, la distancia horizontal recorrida por el esquiador es 101,02 m
