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Elenna [48]
3 years ago
9

How many moles of iron (Fe) can be obtained from 3.80 g iron (III) oxide (Fe2O3) reacting with excess carbon monoxide

Chemistry
1 answer:
topjm [15]3 years ago
3 0

0.02375 moles

Explanation:

Fe2O3+CO :. Fe+CO2

We know that

56*2+16*3=160 gm of Fe2O3 can give 56 gm of Fe

So

3.8 gm can give 1.33 gm of Fe

It is equal to 1.33/56 moles of Fe which is equal to 0.02375 moles

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As the population in a small town grows, a new water treatment plant is built. The plant is built on a local river where it can
xenn [34]

Answer:

A. Treated water from the plant would affect communities downriver.

Explanation:

7 0
4 years ago
All of the following reactions can be described as displacement reactions except:____________.
Lady_Fox [76]

Answer:

b

Explanation:

The reaction that is not a displacement reaction from all the options is C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}

In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

<em>Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.</em>

Correct option = b.

8 0
3 years ago
If you have 5 moles of carbon dioxide at 30degrees C and under 600mmHg of pressure, what will the volume be
trapecia [35]

Answer:

157.64 L

Explanation:

We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 30 °C

T(K) = 30 °C + 273

T (K) = 303 K

Next, we shall convert 600 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

600 mmHg = 600 mmHg × 1 atm / 760 mmHg

600 mmHg = 0.789 atm

Finally, we shall determine the volume of the gas. This can be obtained as follow:

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Pressure (P) = 0.789 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

0.789 × V = 5 × 0.0821 × 303

0.789 × V = 124.3815

Divide both side by 0.789

V = 124.3815 / 0.789

V = 157.64 L

Therefore, the volume of the gas is 157.64 L

7 0
3 years ago
If the solvent front is 68 mm and the ring front of an unknown is 48mm from the original spot, what is the rf value?
Nat2105 [25]

<u>Given:</u>

Distance of solvent front = 68 mm

Distance of unknown = 48 mm

<u>To determine:</u>

The rf value

<u>Explanation:</u>

The retention factor or the rf value is given by the ratio of distance traveled by the unknown to the distance traveled by the solvent front

RF = distance by unknown/distance by solvent

RF = 48/68 = 0.706

Ans: the RF value is 0.706

3 0
3 years ago
Explain why most cells must be microscopic (so small they must be viewed with a microscope) in order to maintain life properly.
Y_Kistochka [10]

Answer:

if the cell grows beyond a certain limit, not enough material  will be able to cross the membrane fast enough to sustain the increased cellular volume

3 0
3 years ago
Read 2 more answers
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