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sergeinik [125]
3 years ago
13

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Chemistry
1 answer:
My name is Ann [436]3 years ago
6 0
Lajdhskskdhskhdksnsjsndjs
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Which are examples of dynamic equilibrium
sweet-ann [11.9K]

Answer:Dynamic Equilibrium Examples. Any reaction will be in dynamic equilibrium if it's reversible and the rates of the forward and reverse reactions are equal. For example, say that you prepare a solution that is saturated with an aqueous solution of NaCl.

Explanation:

8 0
3 years ago
Read 2 more answers
The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick​
Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

     Length x breadth x thickness

        18cm  x   8cm    x    5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part  = length x breadth = 18cm x 8cm  = 144cm

The area of the widest part of the figure is 144cm²

4 0
3 years ago
Match the salt with the acid and base used to form it in a neutralizing reaction.
nignag [31]
<h3><u>Answer;</u></h3>

K2SO4 - KOH and H2SO4

NaBr - NaOH and HBr

<h3><u>Explanation;</u></h3>
  • Salts are compounds that contain positively charged ions and negatively charged ions. That is; they consist of the positive ion of a base and the negative ion of an acid.
  • Salts may be produced when acids and bases are combined together in equal proportions, a process called neutralization.
  • During neutralization reactions an acid reacts with a base to form a salt and water as the only products.
4 0
3 years ago
Read 2 more answers
Automotive air bags inflate when sodium azide, NaN3, decomposes explosively to its constituent elements. How many moles of nitro
attashe74 [19]

Answer:

2.29 g of N2

Explanation:

We have to start with the <u>chemical reaction</u>:

NaN_3~->~Na~+~N_2

The next step is to <u>balance the reaction</u>:

2NaN_3~->~2Na~+~3N_2

We can continue with the <u>mol calculation</u> using the molar mass of

NaN_3 (65 g/mol), so:

3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3

Now, with the<u> molar ratio</u> between NaN_3  and N_2  we can <u>calculate the moles</u> of N_2  (2:3), so:

0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2

With the molar mass of N_2 we can <u>calculate the grams</u>:

0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2

I hope it helps!

5 0
3 years ago
A solution contains 0.10 m sodium cyanide and 0.10 m potassium hydroxide. solid zinc acetate is added slowly to this mixture. wh
Brrunno [24]
1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)

Ksp{Zn(OH)₂}=1.2*10⁻¹⁷

2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)

Ksp{Zn(CN)₂}=2.6*10⁻¹³


Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}

Zn(OH)₂ precipitates first

6 0
3 years ago
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