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sergeinik [125]
2 years ago
13

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Chemistry
1 answer:
My name is Ann [436]2 years ago
6 0
Lajdhskskdhskhdksnsjsndjs
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Aq. sodium oxalate reacts with aq calcium chioride to form sd nd soum ce
STatiana [176]
Na2C2O4(aq) + CaCl2(aq) -----> 2NaCl(aq) + CaC2O4(s)

Here, CaC2O4(s) is a precipitate in the reaction as a result of precipitation reaction or double displacement reaction.

As we know that double displacement reaction two metal ions displaces each other from their salt solutions.

As we know that precipitation reaction is a reaction in which precipitate is formed.
4 0
3 years ago
What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M
professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+]  = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

8 0
2 years ago
What is decarboxylation??<br><br>Gimme one reaction of it..​
kotegsom [21]

Answer:

Decarboxylation is a chemical reaction that removes a carboxyl group and releases carbon dioxide (CO2). Usually, decarboxylation refers to a reaction of carboxylic acids, removing a carbon atom from a carbon chain.

Explanation:

Please give me brainlist

3 0
2 years ago
List some Industrial plants and indicate the gaseous pollutants they emit​
mixas84 [53]

Answer:

Sources of air pollutants from the industry include: power generation plant, boilers, bleaching plants and caustic soda/chlorine plant. Pollutants include particulate matter, chlorine, sulfur dioxides, hydrogen sulfides, carbon dioxide, carbon monoxides and nitrous oxides.

3 0
2 years ago
An Argon laser gives off pulses of green light (wavelength = 514 nm). If a single pulse from the laser has a total energy of 10.
svetoff [14.1K]

Answer:

n=2.59\times 10^{16} photons

Explanation:

E=n\times \frac{h\times c}{\lambda}

Where,  

n is the number of photons

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light

Given that, wavelength = 514 nm = 514\times 10^{-9}\ m

Energy = 10.0 mJ = 0.01 J ( 1 mJ = 0.001 J )

Applying the values as:-

0.01=n\times \frac{6.626\times 10^{-34}\times 3\times 10^8}{514\times 10^{-9}}

\frac{19.878n}{10^{17}\times \:514}=0.01

n=2.59\times 10^{16} photons

7 0
2 years ago
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