What would be the new volume of a gas if 455 of that gas is cooled from 30.0°C to -80.0°C?
2 answers:
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Answer : The correct option is, pressure.
Explanation :
The ideal gas equation is,
where,
P = pressure of the gas
V = volume of the gas
n = number of moles of gas
T = temperature of the gas
R = gas constant
The value of 'R' has several different values which are :
That means, the value of 'R' is different due the change in the pressure value and all the variables (temperature, volume and moles) are constant.
Hence, the correct option is, pressure.
Answer:
220.44g Ba²⁺ ions in solution
Explanation:
Given parameters:
Mass of barium nitrate = 61.2g
Volume of solution = 1 liter
Unkown:
Mass of barium in 7.5quarts of solution?
Solution
We must first convert quarts to its liter equivalence:
1 quarts = 0.95 liter
7.5 quarts = 0.95 x 7.5; 7.125liter
Now, let us find the mass of barium nitrate in a solution of 7.125liter:
Given:
1 liter of solution contains 61.2g of barium nitrate:
7.125 liter will contain 7.125 x 61.2 = 436.05g of barium nitrate.
The formula of the compound is Ba(NO₃)₂:
In solution we have Ba²⁺ + NO₃⁻
Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻
Number of moles of Ba(NO₃)₂ =
Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol
Number of moles of Ba(NO₃)₂ = = 1.609mole
1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution
therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution
Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions x molar mass of Ba²⁺ ions
Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g