3 years ago

What is the value of x and y?

Mathematics

2 answers:

Pavel [41]3 years ago

6 0

Answer:

$x=\boxed{2}$

$y=\boxed{4}$

Step-by-step explanation:

$\begin{cases} y= 6x-8... (1)\\\\y=-3x+10...(2)\end{cases}$

From equations (1) & (2), we find:

6x - 8 = - 3x +10

$\therefore 6x+3x = 8+10$

$\therefore 9x = 18$

$\therefore x =\frac{18}{9}$

$\therefore x = 2$

Plug x = 2 in equation (1)

y = 6(2)-8 = 12-8 =4

So,

$x=\boxed{2}$

$y=\boxed{4}$

hichkok12 [17]3 years ago

6 0

Answer:9X

y10

Step-by-step explanation:

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The length of a rectangle is twice its width. The perimeter of the rectangle is 126ft.

umka21 [38]

Alright, so let's make the length x and the width y. 2y=x, and xy=area. 2x+2y=perimeter. Plugging 2y=x into the perimeter equation, we get that 3x=perimeter=126, and x=126/3=42

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3 years ago

Simplify completely 10x6y3+20x3y2/5x3y

Kryger [21]

Answer:

$\large\boxed{\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=2x^3y^2+4y}$

Step-by-step explanation:

$\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=\dfrac{(5x^3y)(2x^3y^2)+(5x^3y)(4y)}{5x^3y}\\\\=\dfrac{5x^3y(2x^3y^2+4y)}{5x^3y}\qquad\text{cancel}\ 5x^3y\\\\=2x^3y^2+4y$