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Masteriza [31]
4 years ago
7

explains why heating a liquid affects its viscosity? The molecules move faster at higher temperatures and overcome attractions m

ore easily. The molecules move faster at higher temperatures, and the attractions between them increase. The molecules move slower at higher temperatures and overcome attractions more easily. The molecules move slower at higher temperatures, and the attractions between them decrease.
Chemistry
2 answers:
zmey [24]4 years ago
6 0

<span>I think the correct answer is option 1. Heating a liquid affects the viscosity of the liquid because </span><span>molecules move faster at higher temperatures and overcome attractions more easily. Overcoming the attractions in the substance would decrease the viscosity of the liquid.</span>

Aleksandr-060686 [28]4 years ago
3 0

Answer:

i think it is a

Explanation:

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Answer:

M_{K^+}=4.0M \\\\M_{SO_4^{2-}}=2.0M

Explanation:

Hello!

In this case, since the molarity of a solution is defined as the moles of solute divided by the volume of solution liters, given the mass of potassium sulfate, we can compute the moles by using its molar mass (174.24 g/mol):

n_{K_2SO_4}=87gK_2SO_4*\frac{1molK_2SO_4}{174.27gK_2SO_4} =0.50molK_2SO_4

Thus, since one mole of potassium sulfate has two moles of potassium ions (K₂) and one mole of sulfate ions, we can compute the moles of each ion as shown below:

n_{K^+}=0.50molK_2SO_4*\frac{2molK^+}{1molK_2SO_4}=1.0molK^+\\\\ n_{SO_4^{2-}}=0.50molK_2SO_4*\frac{1molSO_4^{2-}}{1molK_2SO_4}=0.50molSO_4^{2-}\\

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M_{K^+}=\frac{1.0mol}{0.250L}=4.0M \\\\M_{SO_4^{2-}}=\frac{0.5mol}{0.250L}=2.0M

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