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Olegator [25]
3 years ago
9

Acceleration of an object

Chemistry
2 answers:
Yuki888 [10]3 years ago
7 0

Answer:

velocity

Explanation:

The definition of acceleration is: Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

Marta_Voda [28]3 years ago
4 0
Velocity is the answer to the question
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Elements in Group 18 are known
o-na [289]

Answer:

C the number and placement of the electrons

Explanation:

Elements react with one another because they want to achieve a full valence shell of electrons. The noble gases already have a full valence shell of electrons, so they are unlikely to react with other elements.

6 0
3 years ago
A hiker climbs a hill. How does the potential energy of the hiker change as she climbs higher?
zloy xaker [14]
The answer should be A
6 0
3 years ago
If 35.0 mL of water in a graduated cylinder is displaced by 8.00 mL
sdas [7]

Answer:

<h2>0.52 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}\\

From the question

volume = final volume of water - initial volume of water

volume = 35 - 8 = 27 mL

We have

density =  \frac{14}{27}  \\  = 0.518518...

We have the final answer as

<h3>0.52 g/mL</h3>

Hope this helps you

3 0
3 years ago
Fe(no3)3 + na0h &gt; fe(oh)3 + nano3 is balanced or unbalanced?
VashaNatasha [74]

Answer:

Unbalanced

Explanation:

\text{Fe}(\text{NO}_3)}_3+ \text{NaOH} \rightarrow \text{Fe(OH)}_3 + \text{NaNO}_3\\\\\text{Balanced reaction:}\\\\\text{Fe}(\text{NO}_3)}_3+ 3\text{NaOH} \rightarrow \text{Fe(OH)}_3 + 3\text{NaNO}_3

5 0
2 years ago
2. A 10 kg ball is rolled down a rail from a height of 20 m. What is the velocity at the bottom of the
solmaris [256]

Answer:

19.8m/s

Explanation:

Given parameters:

Mass of the ball  = 10kg

Height of the rail  = 20m

Unknown:

Velocity at the bottom of the rail  = ?

Solution:

The velocity at the bottom of the rail is its final velocity.

Using the appropriate motion equation, we can find this parameter;

   V²   = U²  + 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

  the ball was rolled from rest, U  = 0

  V²  = O²  + 2 x 9.8 x 20

 V  = 19.8m/s

3 0
3 years ago
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