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stepan [7]
3 years ago
8

The speed of light in air is 3.0 x 10^8 m/s. The speed of light in particular glass is 2.3 x 10^8 m/s. Use the information to de

termine the angle of refraction of light which travels from the glass into air, if the angle of incidence on the glass/air boundary is 25° . Draw a diagram.

Physics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

33.61°

Explanation:

Refractive index is equal to velocity of the light 'c' in empty space divided by the velocity 'v' in the substance.

Or ,

n = c/v.

v is the velocity in the medium  (2.3 × 10⁸ m/s)

c is the speed of light in air = 3.0 × 10⁸ m/s

So,  

n = 3.0 × 10⁸ /  2.3 × 10⁸

n = 1.31

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 25.0° )

{\theta_r} is the angle of refraction  ( ? )

{n_r} is the refractive index of the refraction medium  (air, n=1)

{n_i} is the refractive index of the incidence medium (glass, n=1.31)

Hence,  

1.31\times {sin25.0^0}={1}\times{sin\theta_r}

Angle of refraction = sin^{-1}0.5536 = 33.61°

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