In the 
plane, we have 
everywhere. So in the equation of the sphere, we have
which is a circle centered at (2, -10, 0) of radius 4.
In the 
plane, we have 
, which gives
But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the 
plane, 
, so
which is a circle centered at (0, -10, 3) of radius 
.
The complete question in the attached figure
we know that
triangle OBR is a right triangle
so
<span>applying the Pythagorean theorem
</span>OB²=OR²+RB²----> OB²=3²+4²-----> 25
OB=√25-----> OB=5 units
the answer is OB=5 units
Answer: Perpendicular because the second line has a 2/3 slope and starts at 4.
Answer:
Two dimensional
Step-by-step explanation:
A single plane is a two dimensional platform
cubes and cylinders are both three dimensional objects.
Step-by-step explanation:
y = ax + b
a is the slope of the line. it is expressed as the ratio
y coordinate change / x coordinate change
when going from one point to the other.
b is the y-intercept (the y value when x = 0).
once we have the slope, we get b by using the coordinates of one of the given points as x and y in the equation and solve for b. or we get the point of the line directly on the y-axis.
we see several marked points.
e.g.
(-4, 4) (0, -4)
x changes by +4 (from -4 to 0)
y changes by -8 (from 4 to -4)
the slope (a) is -8/+4 = -2
the y-intercept is given by the point (0, -4), because this is where x=0.
so, it is -4
and the line equation is
y = -2x - 4
