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Natasha2012 [34]
3 years ago
7

A 0.900-V potential difference is maintained across a 1.5m length of 2

Physics
1 answer:
Daniel [21]3 years ago
3 0

Answer:

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section, A=0.6\ mm^2=6\times 10^{-7}\ m^2

We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :

V = IR

Where R is the resistance of the wire

I=\dfrac{V}{R}\\\\I=\dfrac{V}{\rho \dfrac{l}{A}}\\\\I=\dfrac{0.9}{5.6\times 10^{-8}\times \dfrac{1.5}{6\times 10^{-7}}}\\\\I=6.42\ A

So, the current in the wire is 6.42 A.

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A 5.50 kg sled is initially at rest on a frictionless horizontal road. The sled is pulled a distance of 3.20 m by a force of 25.
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(b) 0

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(c) 69.3 J

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W = 69.3 J

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The change in kinetic energy of the sled can be rewritten as:

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3 0
3 years ago
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