A mixture of hept-1-yne, hept-2-yne, and hept-3-yne was hydrogenated in the presence of a platinum catalyst until hydrogen uptak
e ceased. If one assumes that the hydrogenation went to completion, how many different seven-carbon hydrocarbons were produced?
1 answer:
Answer:
Only one seven carbon hydrocarbon was produced.
Explanation:
- Alkynes are reduced completely in presence of
to produce alkanes.
- Hydrogenation in presence of Pt is a simple nucleophilic addition process where
molecule adds onto an unsaturated bond.
- Hept-1-yne, hept-2-yne and hept-3-yne are constitutionally isomeric to each other. Hence, after complete reduction, all three alkynes produced heptane as only product.
- So, only one seven carbon hydrocarbon was produced.
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Answer:
a) 2-bromopyrrole
Explanation:
Our options for this questions are:
a) 2-bromopyrrole
b) 2,3-dibromopyrrole
c) N-bromopyrrole
d) 3-bromopyrrole
To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.
The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the and
. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).
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