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ioda
3 years ago
8

A mixture of hept-1-yne, hept-2-yne, and hept-3-yne was hydrogenated in the presence of a platinum catalyst until hydrogen uptak

e ceased. If one assumes that the hydrogenation went to completion, how many different seven-carbon hydrocarbons were produced?

Chemistry
1 answer:
arsen [322]3 years ago
4 0

Answer:

Only one seven carbon hydrocarbon was produced.

Explanation:

  • Alkynes are reduced completely in presence of Pt/H_{2} to produce alkanes.
  • Hydrogenation in presence of Pt is a simple nucleophilic addition process where H_{2} molecule adds onto an unsaturated bond.
  • Hept-1-yne, hept-2-yne and hept-3-yne are constitutionally isomeric to each other. Hence, after complete reduction, all three alkynes produced heptane as only product.
  • So, only one seven carbon hydrocarbon was produced.

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Answer:

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NO2      0        0 + x          x

∴ x = neq = Peq.V / R.T.....ideal gas mix

if P = 0.5 atm, T = 25°C; assuming: V = 1 L

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3 years ago
What is the mass of HCL is consumed by the reaction of 1.5 mole of magnesium
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1.67×10^25 molecules

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3 years ago
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