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ioda
3 years ago
8

A mixture of hept-1-yne, hept-2-yne, and hept-3-yne was hydrogenated in the presence of a platinum catalyst until hydrogen uptak

e ceased. If one assumes that the hydrogenation went to completion, how many different seven-carbon hydrocarbons were produced?

Chemistry
1 answer:
arsen [322]3 years ago
4 0

Answer:

Only one seven carbon hydrocarbon was produced.

Explanation:

  • Alkynes are reduced completely in presence of Pt/H_{2} to produce alkanes.
  • Hydrogenation in presence of Pt is a simple nucleophilic addition process where H_{2} molecule adds onto an unsaturated bond.
  • Hept-1-yne, hept-2-yne and hept-3-yne are constitutionally isomeric to each other. Hence, after complete reduction, all three alkynes produced heptane as only product.
  • So, only one seven carbon hydrocarbon was produced.

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Determine the oxidation state of the metal ion in [co(nh3)5br]2+. express your answer as an integer.
Zanzabum
                                           [Co(NH₃)₅Br]²⁺

Ligands and charges on them,

                             5 × NH₃  =  5 × 0  =  0

                             1 × Br⁻¹  =  1 × -1  =  -1

Charge on sphere  =  +2

So, putting values in equation,

                                       Co + (0)₅ - 1  =  +2

                                       Co + 0 - 1  =  +2

                                       Co - 1  =  +2

                                       Co  =  +2 + 1

                                       Co  =  +3

Result:
           Oxidation state of Co in [Co(NH₃)₅Br]²⁺ is +3.
7 0
3 years ago
What happens to the speed of motion of the particles of a gas when a certain volume of the gas is heated at constant pressure? E
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Energy of electrons depends on light’s frequency, not intensity.

As per photoelectric effect, if we incident a light on metal surface it will results into emission of electron from it

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3 years ago
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Explanation:

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