A mixture of hept-1-yne, hept-2-yne, and hept-3-yne was hydrogenated in the presence of a platinum catalyst until hydrogen uptak
e ceased. If one assumes that the hydrogenation went to completion, how many different seven-carbon hydrocarbons were produced?
1 answer:
Answer:
Only one seven carbon hydrocarbon was produced.
Explanation:
- Alkynes are reduced completely in presence of
to produce alkanes.
- Hydrogenation in presence of Pt is a simple nucleophilic addition process where
molecule adds onto an unsaturated bond.
- Hept-1-yne, hept-2-yne and hept-3-yne are constitutionally isomeric to each other. Hence, after complete reduction, all three alkynes produced heptane as only product.
- So, only one seven carbon hydrocarbon was produced.
You might be interested in
Given :
Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .
To Find :
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .
Solution :
By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.
So , volume of solution does not matter .
Moles of oxygen , .
Now , molecule of CO contains 1 mole of C .
So , moles of C is also 0.167 mole .
Mass of carbon , .
Therefore , mass of carbon is 2 grams .
Hence , this is the required solution .