Answer:
neq N2O4 = 0.9795 mol.....P = 0.5 atm; T = 25°C
Explanation:
ni change eq.
N2O4 1 1 - x 0.8154.....P = 1 atm; T = 25°C
NO2 0 0 + x x
∴ x = neq = Peq.V / R.T.....ideal gas mix
if P = 0.5 atm, T = 25°C; assuming: V = 1 L
⇒ x = neq = ((0.5 atm)(1 L))/((0.082 atm.L/K.mol)(298 K))
⇒ x = neq = 0.0205 mol
⇒ neq N2O4 = 1 - x = 1 - 0.0205 = 0.9795 mol
Answer: 109.5g
Explanation:
Mg + 2HCl —> MgCl2 + H2
From the equation,
1mole of Mg required 2moles of HCl
Therefore 1.5moles of Mg will require = 1.5 x 2 = 3 moles of HCl.
Molar Mass of HCl = 1+35.5 =36.5g/mol
Mass conc. Of HCl = 3 x 36.5 = 109.5g
sorry but I don't know so sorry
No, They need something to hold on to, such as dirt
Answer:
1.67×10^25 molecules
Explanation:
No of molecules = no of moles × Avogadros number
No of moles= mass in gram / molar mass
No of moles of water in given sample = 500.3/18
= 27.79 moles
No of molecules = 27.79× 6.02×10^ 23
= 167.32×10^23 or 1.67×10^25