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3 years ago

5

A man lifts a 200 pound barbell over his head using 890 Newtons of force. It traveled a distance of 2.4 meters. Calculate the wo

rk done.
A. 2,136j
B. 83j
C. 371j
D. 480j

1 answer:

N76 [4]3 years ago

5 0

Answer:

371j

Explanation:

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Explanation:

This problem relates to interference of light in thin films .

The condition of bright fringe in thin films which is sandwitched by two layers of medium having lesser refractive index is as follows.

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2 x 1.5 t = 600 / 2 nm

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Answer:

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How much meters is a mile

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A leopard with a mass of 55.00 kg climbs 12.0 m up a tree. What is it’s gain in GPE

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The answer is: 6,468 j

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The magnitude of Earth’s magnetic field is about 0.5 gauss near Earth’s surface. What’s the maximum possible magnetic force on a

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Answer:

$F = 1.5 \times 10^{-16} N$

this force is $1.68 \times 10^{13}$ times more than the gravitational force

Explanation:

Kinetic Energy of the electron is given as

$KE = 1 keV$

$KE = 1 \times 10^3 (1.6 \times 10^{-19}) J$

$KE = 1.6 \times 10^{-16} J$

now the speed of electron is given as

$KE = \frac{1}{2}mv^2$

now we have

$v = \sqrt{\frac{2 KE}{m}}$

$v = 1.87 \times 10^7 m/s$

now the maximum force due to magnetic field is given as

$F = qvB$

$F = (1.6\times 10^{-19})(1.87 \times 10^7)(0.5 \times 10^{-4})$

$F = 1.5 \times 10^{-16} N$

Now if this force is compared by the gravitational force on the electron then it is

$\frac{F}{F_g} = \frac{1.5 \times 10^{-16}}{9.1 \times 10^{-31} (9.8)}$

$\frac{F}{F_g} = 1.68 \times 10^{13}$

so this force is $1.68 \times 10^{13}$ times more than the gravitational force

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3 years ago