1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kitty [74]
3 years ago
5

A man lifts a 200 pound barbell over his head using 890 Newtons of force. It traveled a distance of 2.4 meters. Calculate the wo

rk done.
A. 2,136j
B. 83j
C. 371j
D. 480j​
Physics
1 answer:
N76 [4]3 years ago
5 0

Answer:

371j

Explanation:

You might be interested in
How do mass and distance affect gravity?
elixir [45]
A gravitational force between objects depends on two things- their masses and the distance between them. So the greater the mass and the less distance there is, the more gravitational force and is the mass is less and the distance is great the gravitational force is weak
5 0
3 years ago
A ball of mass 0.50 kg is fired with velocity 160 m/s into the barrel of a spring gun of mass 1.8 kg initially at rest on a fric
shepuryov [24]

Answer:

All fraction of kinectic energy is lost to barrel of a spring gun of mass 1.8 kg

Explanation:

A ball of mass 0.50 kg is fired with velocity 160 m/s ...

The kinetic energy is given by 1/2mv²

Kinectic energy of the ball = 1/2 *0.5*160²

Kinectic energy = 1/4 *25600

Kinectic energy = 6400 joules.

If no energy is lost to fiction, and the ball sticks to a barrel of a spring gun of mass 1.8 kg with initial velocity zero, all kinetic energy is lost to the barrel of a spring gun of mass 1.8 kg.

5 0
3 years ago
I need help with this Physics question!
just olya [345]
Mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
7 0
3 years ago
An electron is moving in a circular orbit in a uniform magnetic field. Is the kinetic energy of the electron changing?
Lelechka [254]

Answer:

kinetic energy does not change

Explanation:

you can use the formula for the kinetic energy of the electron and for the radius of the trajectory of an electron in a uniform magnetic field:

E_k=\frac{1}{2}m_ev^2\\\\r=\frac{m_e v}{qB}

me: mass of the electron

B: magnetic field

q: charge of the electron

r: radius

By doing v the subject of the formula and replace it in the expression for the kinetic energy you obtain:

v=\frac{rqB}{m_e}\\\\E_k=\frac{1}{2}m_e(\frac{rqB}{m_e})^2=\frac{r^2q^2B^2}{2m_e}

as youcan see, all parameters r, q, B and me are constant.

hence, the kinetic energy does not change

3 0
3 years ago
Sound is caused by the _____ air particles (waves)
Sav [38]

Answer:

Sound travels in air as a series of compressions and rarefactions. When an object vibrates it will move back and forth. As it moves forth, it pushes adjacent air particles. ... This is a compression: an area of high pressure that moves along the direction of the sound wave.

Explanation:

adjacent is the answer

5 0
3 years ago
Other questions:
  • What are examples of chemical energy
    11·1 answer
  • Lactic acid is produced during low-moderate exercise <br> True <br> False
    15·2 answers
  • A small space probe of mass 170 kg is launched from a spacecraft near Mars. It travels toward the surface of Mars, where it will
    6·1 answer
  • What is systematic error​
    5·2 answers
  • Suppose the sphere is electrically neutral. Is it attracted to
    9·1 answer
  • Assume you have an ice cube and also a small rock that is the same size and shape as the ice cube. Predict what would happen if
    10·1 answer
  • What current flows through a 2.54cm diameter rod of pure silicon that is 20cm long when 1000V is applied?
    5·1 answer
  • An inclined plane creates a mechanical advantage of 5. What would the input force need to be to create an output force of 20 N?
    12·1 answer
  • Two risks of exposure to High levels of UV radiation
    10·2 answers
  • In the formula V = TR, the "I" means <br>O static charge <br>O current <br>O isotope<br>O immunity​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!