Answer:
Force=7.71KN in the opposite direction
Explanation:
Given the mass of the car(M)=1000Kg
The initial speed of the car(u)=100km/hr
we know that 1km/hr=5/18 m/sec
100km/hr=100*5/18 m/sec=27.77m/sec
the distance travelled before it stops (s)=50m
let the acceleration of the car be a
The final velocity of the car is 0.
we know that 
a=7.712m/
We know that F=Ma
F=1000* 7.712=7712N=7.71KN
Y = 42t - 16t^2
velocity = vt = dy/dt
= 42 - 32t
v(1) = 42 - 32
= 10 ft/s
Hope this helps
Answer: A car slows from 22 m/s to 3.0 m/s at a constant rate of 2.1 m/s2. How many seconds are required before the car is a r2.1 m/s2 traveling at 3.0 m/s?
5 pages
Explanation:
Answer:
Work done W 2.938*10^9 J
Explanation:
given data:
mass m = 944 Kg
Mass of moon M = 7*10^22 Kg
Radius of the moon R = 1.5*10^6 m
gravitational constant G = 6.67*10^{-11} Nm^2/Kg^2
we know that work done is given as
Work done 
= 2.938*10^9 J
I believe the answer is D. It is D because Mercury is the closest planet to the sun and has the greatest gravitational attraction between the sun
