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Zanzabum
3 years ago
8

Describe kepler's contribution to the current structure of the solar system.

Physics
1 answer:
notka56 [123]3 years ago
7 0
Kepler used mathematics to determine the paths of planets around the sun
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The Doppler shift can be observed when ____________. Check all that apply. Group of answer choices the source of sound moves tow
castortr0y [4]

Answer:

the source of sound moves towards an observe

Explanation:

The Doppler effect is related to waves such as sound or light. the effect causes an increase or decrease in the frequency of sound light or other waves when the souces either move towards or away from the observer. For example the siren of the train to a person on the platform, the redshift seen by astronomers.

Therefore, The Doppler shift can be observed when the source of sound moves towards an observer From a place closer to the observer than the last wave's crest, each consecutive wave crest is sent. Each wave therefore, takes a little less time than the preceding wave to reach the observer.

6 0
3 years ago
A pendulum with a length of 1.00 m is released from an initial angle of 12.5°. After 1 000 s, its amplitude has been reduced by
Viefleur [7K]

Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

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7 0
2 years ago
Which is a result if using a machine
hammer [34]
There are many types of machine what type well for every day machines like treadmills is sweating, dehydration, loss of calories or fat.
6 0
3 years ago
Name two objects that both use electric motors and are commonly found in houses
Natali [406]
There's the fan over the stove and in the microwave oven, the dispose-all under the sink, the blender, the washer, the dryer, vacuum cleaner, hair dryer, and there are many in a computer.

Hope this helps!
3 0
3 years ago
Read 2 more answers
The free-fall acceleration at the surface of planet 1 is 26 m/s^2 . The radius and the mass of planet 2 are twice those of plane
valkas [14]

Answer:

13 m/s^2

Explanation:

The acceleration of gravity near the surface of a planet is:

g = MG / R^2

For planet 1, g = 26 m/s^2.

The gravity on planet 2 in terms of the mass and radius of planet 1 is:

g = (2M)G / (2R^2)

g = 1/2 MG / R^2

Since MG/R^2 = 26 m/s^2, then:

g = 13 m/s^2

6 0
3 years ago
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