Answer:
The probability that the household has only cell phones and has high-speed Internet is 0.408
Step-by-step explanation:
Let A be the event that represents U.S. households has only cell phones
Let B be the event that represents U.S. households have high-speed Internet.
We are given that 51% of U.S. households has only cell phones
P(A)=0.51
We are given that 70% of the U.S. households have high-speed Internet.
P(B)=0.7
We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.
P(B|A)=0.8
![\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408](https://tex.z-dn.net/?f=%5Cfrac%7BP%28A%5CcapB%29%7D%7BP%28A%29%7D%3D0.8%5C%5CP%28A%5CcapB%29%3D0.8%20%5Ctimes%20P%28A%29%5C%5CP%28A%5CcapB%29%3D0.8%20%5Ctimes%200.51%5C%5CP%28A%5CcapB%29%3D0.408)
Hence the probability that the household has only cell phones and has high-speed Internet is 0.408
I just did it on paper but hope that helps:)
The trinomial that results from foiling the binomials is 6x^2+41x+30.
Answer:
b is the answer i think
Step-by-step explanation:
I learned this at some point
Answer: F: I only
Step-by-step explanation: