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tekilochka [14]
2 years ago
11

Strontium-90 is one of the products of the fission of uranium-235. This strontium isotope is radioactive, with a half-life of 28

.1 yr. Calculate how long it will take for 0.900 g of the isotope to be reduced to 0.170 g by decay.
Chemistry
1 answer:
Firlakuza [10]2 years ago
5 0

Answer:

67.6 years is the time the isotope take to decay from 0.900g to 0.170g

Explanation:

The radioactive decay follows first order law:

Ln [A] = -kt + ln[A]₀

<em>Where [A] is concentration after time t,</em>

<em>k is decay constant:</em>

<em>k = ln 2 / t(1/2)</em>

<em>k = ln2 / 28.1 years</em>

<em>k = 0.02467 years⁻¹</em>

<em>[A]₀ = Initial concentration.</em>

<em />

We can replace concentration and use the mass of the isotope:

Ln [A] = -kt + ln[A]₀

Ln [0.170g] = -0.02467 years⁻¹t + ln[0.900g]

-1.667 = -0.02467 years⁻¹t

t =

<h3>67.6 years is the time the isotope take to decay from 0.900g to 0.170g</h3>
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A 0.98 gram sample of a volatile liquid was heated to 348 k. the gas occupied 265 ml of space at a pressure of 0.95 atm. what is
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The molecular weight is Z =  111.2 \ g/mol

Explanation:

From the question we are told that

   The mass of the sample is  m =  0.98 \  g

    The temperature is  T  =  348 K

    The volume which the gas occupied is  V  =  265 \ ml  = 265 *10^{-3} L

     The pressure is  P  =  0.95 \  atm

Generally from the ideal gas equation we have that

       PV  =  n RT

Here n is the number of moles of the gas while the R is the gas constant with value  R  =  0.0821 \ atm \cdot L  \cdot mol^{-1} \cdot K^{-1}

        n = \frac{PV}{ RT}

=>      n = \frac{ 0.95 * 265 *10^{-3} }{   0.0821 * 348}

=>      n = 0.00881 \  mol

Generally the molecular weight is mathematically represented as

          Z =  \frac{m}{n}

=>      Z =  \frac{0.98 }{0.00881}

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