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Ymorist [56]
3 years ago
11

When storing parts outside it is best to keep them under tarps or wrapped to stay in compliance. T or F

Chemistry
2 answers:
alex41 [277]3 years ago
6 0

Answer : True

Explanation : When storing parts outside it is best to keep them under tarps or wrapped to stay in compliance is true, because when we store the parts outside the house there are high chances of the parts getting exposed to environmental moisture. Which will develop rust on the parts and make it useless later on. To avoid this situation it is safer to keep it covered under the tarps or wrap it with something which can protect it from moisture.

tatiyna3 years ago
4 0
When it comes to leaving parts outside, it is True. It's a good idea to keep them wrapped or under tarps to stay in Compliance!
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45.6 mL of 0.0600 M Ba(OH)2 is added to 25.0 mL of HCl of unknown concentration. What is the concentration of HCl?
Alex Ar [27]

45.6 mL of 0.0600 M of Ba(OH)_{2} is added to 25.0 mL of HCl of unknown concentration then , the  concentration of HCl is 0.032 M .

Calculation ,

Formula used : M_{1} V_{1} =  M_{2} V_{2}                 ...( 1 )

Where  M_{1}= concentration of Ba(OH)_{2}  =  0.0600 M ( given )

M_{2} = concentration of HCl = ? ( to be find )

 V_{1}= volume of Ba(OH)_{2}  = 25.0 mL  ( given )

V_{2} = volume of HCl = 45.6 mL  ( given )

Now , put the value of all volume and concentration in equation ( 1 ) we get .

0.0600 M ×  25.0 mL =  M_{2}  × 45.6 mL

M_{2}  =  0.0600 M ×  25.0 mL / 45.6 mL = 0.032 M

Therefore , concentration of  unknown concentration of HCl is 0.032 M .

to learn about concentration here ,

brainly.com/question/10725862

#SPJ1

7 0
1 year ago
HELP! THIS IS SCIENCE
Alexxx [7]
This is known as Rutherford's gold foil experiment. To align with J.J Thompson's Plum Pudding Model, he expects a beam of alpha particles to just pass through the gold foil undisturbed. However, some were deflected at certain angles. Alpha particles are positive, so it would just go straight through the nucleus, but will deflect if it hits the electrons. <em>Therefore, the answer is: </em><span><em>Particles that struck the nucleus went straight.</em></span>
7 0
3 years ago
Read 2 more answers
A compound is found to contain 26.73 % phosphorus, 12.09 % nitrogen, and 61.18 % chlorine by mass. What is the empirical formula
Mrrafil [7]

Answer:

PNCl_2

Explanation:

Hello!

In this case, when determining empirical formulas by knowing the by-mass percent, we first must assume the percentages as masses so we can compute the moles of each element:

n_P=\frac{26.73g}{30.97g/mol}=0.863mol\\\\n_N=\frac{12.09g}{14.01g/mol}=0.863mol\\\\n_C_l=\frac{61.18g}{35.45g/mol}=1.726mol

Now, for the determination of the subscript of each element in the empirical formula, we divide the moles by the fewest moles (P or N):

P=\frac{0.863mol}{0.863mol}=1\\\\N= \frac{0.863mol}{0.863mol}=1\\\\Cl=\frac{1.726mol}{0.863mol}2

Thus, the empirical formula is:

PNCl_2

Regards!

4 0
2 years ago
A model used for the yield Y of an agricultural crop as a function of the nitrogen level N in the soil (measured in appropriate
lisov135 [29]

Answer:

  • It is 3.

Explanation:

The model written correctly is:

  • Y=\frac{kN}{9+N^2}

This is a mathematical question, instead of a chemistry question, and you should use calculus to find the nitrogen level that gives the best yield, since this is an optimization problem.

The best yield is the maximum yield, and the maximum, provided that it exists, is found using the first derivative and making it equal to zero: Y' = 0

To find Y' you must use the quotient rule.

Y'=\frac{(kN)'(9+N^2)- (kN)(9+N^2)'}{(9+N^2)^2}\\ \\Y'=\frac{k(9+N^2)-kN(2N)}{(9+N^2)^2}\\ \\Y'=\frac{9k + kN^2 - 2kN^2}{(9 + N^2)^2}=\frac{9k-kN^2}{(9+N^2)^2}

Now make Y' = 0

  • The denominator is never equal to zero, because it is always positive and greater than 9.

  • Make the numerator equal to zero:

         9k - kN² = 0

  • Factor: k (9 - N²) = 0

  • Since k is a positve constant, it is not equal to zero, and the other factor, 9 - N², must be equal to zero:

         9 - N² = 0 ⇒ (3 - N) (3 + N) = 0

         ⇒ 3 - N = 0 or 3 + N = 0 ⇒ N = 3 or N = -3.

Since N is nitrogen level, it cannot be negative and the only valid answer is N = 3.

You can prove that it is a maximum (instead of a minimum) finding the second derivative or testing some points around 3 (e.g. 2.5 and 3.5).

8 0
3 years ago
200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?
Ipatiy [6.2K]
  • M be molar concentration
  • V be volume

So

  • M1=0.845M
  • V1=200mL=0.2L
  • V2=0.6L
  • M2=?

\\ \tt\rightarrowtail M1V1=M2V2

\\ \tt\rightarrowtail 0.845(0.2)=0.6M2

\\ \tt\rightarrowtail 0.169=0.6M2

\\ \tt\rightarrowtail M2=0.281M

7 0
2 years ago
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