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notsponge [240]
3 years ago
6

A) Both A and R are true and R is the correct explanation of the assertion.

Physics
2 answers:
avanturin [10]3 years ago
5 0
Hey pls don’t. Report my answer I’m in a test and I rlly want someone to answer my question
ddd [48]3 years ago
4 0
The answer is C then
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saw5 [17]

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5 0
3 years ago
A coil of conducting wire carries a current of i(t) = 14.0 sin(1.15 ✕ 103t), where i is in amperes and t is in seconds. A second
Advocard [28]

Answer:

The peak emf in second coil is 1.876 V

Explanation:

Given :

Inductance L = 130 \times 10^{-6} H

The current I(t) = 14 \sin(1.15\times 10^{3} t)

We compare above equation with standard equation,

  I(t) = I_{o} \sin (\omega t + \phi)

From above equation we have,

  \omega = 10^{3} and \phi = 1.15

Find the inductive resistance,

  X_{L} = \omega L

  X_{L} = 10^{3}  \times 130  \times 10^{-6}

  X_{L} = 0.134

The peak emf in second coil is,

   V = I_{o} X_{L}

  V = 14 \times 0.134

  V = 1.876 V

Therefore, the peak emf in second coil is 1.876 V

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4 years ago
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algol [13]

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