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Gwar [14]
3 years ago
15

A wave travelling 140 m/sec with a wavelength of 4.0 m has what frequency? _______________Meters / Hz / seconds

Physics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

The frequency of a wave is 35 Hz.

Explanation:

Speed of a wave is 140 m/s

Wavelength of a wave is 4 m

It is required to find the frequency. The relation between frequency, speed and the wavelength of a wave is given by :

v=f\lambda

f is frequency

f=\dfrac{v}{\lambda}\\\\f=\dfrac{140\ m/s}{4\ m}\\\\f=35\ Hz

So, the frequency of a wave is 35 Hz.

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Nesterboy [21]

Answer:

mass multiplied by velocity (4 words but uh

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2 years ago
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20. GP A sinusoidal wave traveling in the negative x direction (to the left) has an amplitude of 20.0cm, a wavelength of 35.0cm,
umka21 [38]

The angular frequency of the wave is determined as 75.4 rad/s.

<h3>What is wave function?</h3>

A wave function is a mathematical equation for the motion of the wave.

y(x, t) = A sin(kx + ωt + Φ)

where;

  • ω is angular speed
  • k is angular wavenumber
  • Φ is phase angle

<h3>What is angular frequency?</h3>

The angular frequency is the angular displacement of any wave element per unit of time or the rate of change of the waveform phase.

<h3>Angular frequency</h3>

ω = 2πf

ω = 2π(12)

ω = 75.4 rad/s

Thus, the angular frequency of the wave is determined as 75.4 rad/s.

Learn more about angular frequency here: brainly.com/question/3654452

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7 0
2 years ago
One kilogram-meter per second squared is also equal to what unit
yan [13]
Metres/second² is acceleration. maybe a bit more clarification?

8 0
3 years ago
Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.9 m tall window in 0.134 sec. From how high above th
timama [110]

Answer:

Explanation:

Given

length of window h=2.9\ m

time Frame for which rock can be seen is \Delta t=0.134\ s

Suppose h is height above which rock is dropped

Time taken to cover h+2.9 is t_1

so using equation of motion

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

time taken to travel h  is

h=0+0.5\times g\times (t_2)^2---2

Subtract 1 and 2 we get

2.9=0.5g(t_1^2-t_2^2)

5.8=g(t_1+t_2)(t_1-t_2))

and from equation t_1-t_2=0.134\ s

so t_1+t_2=\frac{5.8}{9.8\times 0.134}

t_1+t_2=4.416\ s

and t_1=t_2+\Delta t

so t_2+\Delta t+t_2=4.416

2t_2+0.134=4.416

t_2=0.5\times 4.282

t_2=2.141\ s

substitute the value of t_2 in equation 2

h=0.5\times 9.8\times (2.141)^2

h=22.46\ m

                                                     

8 0
4 years ago
. If you live in a region that has a particular TV station, you can sometimes pick up some of its audio portion on your FM radio
Reil [10]

Answer:

Please see below as the answer is self-explanatory.

Explanation:

The low band of the VHF TV Spectrum, spans channels 2-6, from 54 to 88 Mhz.

In the analog TV, in the Americas, the total bandwidth of any channel is 6 Mhz, with the visual carrier modulated in VSS (Vestigial Side Band) at 1.25 Mhz from the lowest frequency of the channel.

The aural carrier is located at 4.5 Mhz from the visual carrier, and is FM modulated.

For Channel 6, which spans between 82 and  88 Mhz, the visual carrier is at 83.25 Mhz, so the aural carrier is at 87.75 Mhz, which falls within the FM Band, so it is possible to listen the audio part of this channel in a FM radio receiver, even at a lower volume, due to the FM radio has a greater deviation than TV aural carrier.

6 0
4 years ago
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