Question

The Starship Enterprise returns from warp drive to ordinary space with a forward speed of 54 km/s . To the crew's great surprise, a Klingon ship is 110 km directly ahead, traveling in the same direction at a mere 22 km/s. Without evasive action, the Enterprise will overtake and collide with the Klingons in just about 3.4 s. The Enterprise's computers react instantly to brake the ship. What magnitude acceleration does the Enterprise need to just barely avoid a collision with the Klingon ship?

Answer 1

Answer:

The acceleration will be "-5.12 km/s²".

Explanation:

The given values are:

This might be defined as a continuous inanimate object at either the speed between such organization as well as the Klingon boat (54 - 22) km/s.  

The values given in the question are:

= 110 km

Final velocity will be:

= 0

By using to the third equation of motion, we get

⇒ $v^2=u^2+2as$

     $0=(54-22)^2+2\times a\times 100$

     $0=(32)^2+2\times a\times 100$

     $0=1024+2\times a\times 100$

     $0=1024+200a$

     $-1024=200a$

             $a=-\frac{1024}{200}$

                $=-5.12 \ km/s^2$