Answer: 4.64 × 10^7 mg
Explanation:
Given:
T =1299g + 45.1kg
Convert kg to g
T = 1299g + 45.1kg ×1000g/kg
T = 1299g + 45100g
T = 46399g
T= 4.64 × 10^4 g
Convert to milligram
T = 4.64 × 10^4 g × 1000mg/g
T = 4.64 × 10^7 mg
Therefore, 1299g + 45.1kg = 4.64 × 10^7 mg
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Given a steel rod:
Radius = r = 10 mm = 0.010 m.
Length L = 1 m.
Tensile Force = F = 100 kN.
Young's Modulus = Y = 2.0 &* 10¹¹ Nm⁻²
a) Stress = Force/cross sectional area
σ = F / A
= 100,000 /(π 0.010²) Pa
= 318.309 MPa
b) Y = (F/A) / (ΔL/L)
Elongation ΔL = L F / (A Y)
= L σ / Y
= 1 * 318.309 * 10⁶ / 2.0 * 10¹¹ m
= 1.591 mm
c) Percentage elongation : ΔL/L * 100 = 0.1591 %
Answer:
1/4 as much
Explanation:
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