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algol [13]
3 years ago
6

The value of the function g(x) is –2 when x = -5 and is 5.7 when x = 6. What is

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:  the equation of function g(x) is y=0.7 x+ 1.5

Step-by-step explanation: The value of the function g(x) is −2 when x=−5. It means the graph of function passes through (-5,-2).

The value of the function g(x) is 5.7 when x=6. It means the graph of function passes through (6,5.7).

The equation of function g(x) that passes through (-5,-2) and (6,5.7) is

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We know from the slope intercept form that y=mx+b so the y intercept is 12 while every hour the cost goes up by 8
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What is the length of DE?
miskamm [114]

Answer:

11

Step-by-step explanation:

If two chords intersect in a circle, the product of the lengths of the segments of one chord equal the product of the segments of the other.

AC *CB = CD CE

4 * (10-4) = CD * 8

4 * 6 = 8 *CD

24 = 8 CD

Divide each side by 8

24/8 = CD

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We want the length DE

DE = CD + CE

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3 years ago
State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
DENIUS [597]

Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

It is given that \:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7

We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

\:f\left(x-7\right)= \sqrt{3x-21-2}

\:f\left(x-7\right)= \sqrt{3x-23}

From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

x\geq\frac{23}{3}

The value of x is all real number greater than \frac{23}{3}.

Hence, the interval notation for the domain is [\frac{23}{3},\infty  ].

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\frac{8x-12}{2}

Step-by-step explanation:

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