How many moles of water are needed in order to produce 218 g of calcium

Which state of matter has a definite volume but no specific shape

Nadya [2.5K]

Liquid has a definite volume but no specific shape

3 0

4 years ago

Which kind of substance needs more energy to undergo an increase of 25 degrees Celsius something with a high or low specific hea

Nikolay [14]

The substance that needs more energy to undergo an increase of 25°C will have a higher specific heat, because energy depends directly on specific heat.

Q = cm∆T
where c = specific heat of the substance,
m = mass
∆T = temperature difference

3 0

3 years ago

20.1 g of aluminum and 219 g of chlorine gas react until all of the aluminum metal has been converted to AlCl3. The balanced equ

Romashka-Z-Leto [24]

Answer:

The amount of Cl2 gas left , after the reaction goes to completion is : 139.655 grams

Explanation:

Molar mass : It is the mass in grams present in one mole of the substance.

Moles of the substance is calculated by:

$Moles=\frac{Mass}{Molar\ mass}$

$2Al(s)+3Cl_{2}(g)\leftarrow 2AlCl_{3}(g)$

According to this equation:

2 mole of Al = 3 mole of Cl2 = 2 mole of AlCl3

Molar mass of Al = 27.0 g/mol

Mass of Al = 20.1 gram

Moles of Al present in the reaction :

$Moles=\frac{Mass}{Molar\ mass}$

$Moles=\frac{20.1}{26.98}$

Moles of Al = 0.744

Similarly calculate the moles of Cl2

Molar mass of Cl2 = 71.0 g/mol

Mass = 219 gram

$Moles=\frac{Mass}{Molar\ mass}$

$Moles=\frac{219}{70.98}$

Moles of Cl2 = 3.08 moles

According to equation,

2 mole of Al reacts with = 3 mole of Cl2

1 moles of Al reacts with = 3/2 mole of Cl2

0.744 moles of Al reacts with = 3/2(0.744) moles of Cl2

= 1.116 moles of Cl2

But actually present Cl2 = 3.08 moles

Hence Al is the limiting reagent , and Cl2 is the excess reagent.

The whole Aluminium Al get consumed during the reaction.

The amount of Cl2 in excess = Total Cl2 - Cl2 consumed

Cl2 in excess = 3.08 - 1.116 = 1.964 moles

Cl2 in grams = 1.964 x 70.90 = 139.655 grams

6 0

4 years ago

The first system of classification of organisms was developed by____.

zhuklara [117]

C. Linnaeus The Swedish botanist Carl Linnaeus is regarded as the father of taxonomy, as he developed a system known as Linnaean classification for categorization of organisms and binomial nomenclature for naming organisms.

4 0

4 years ago

Read 2 more answers

A chemistry student weighs out of acetic acid into a volumetric flask and dilutes to the mark with distilled water. He plans to

xeze [42]

Answer:

Your question is not complete, but use this answer as a guide for your solution.

Question: A chemistry student weighs out 0.112g of acetic acid (HCH₃CO₂) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1600 M NaOH solution. Calculate the volume of solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits.

Answer: Volume of NaOH is 11.6 mL

Explanation:

The reaction of acetic acid with NaOH is as follows:

CH3COOH + NaOH -----> CH3COONa + H2O

M1V1 = M2V2

Here M1 V1 are molarity and volume of acetic acid.

M2, V2 are molarity and volume of NaOH.

Number of moles of acetic acid:

0.112 g CH3COOH × (1 mol / 60.05 g) = 0.001865 mol

Molarity = moles of solute / Liters of solution

Molarity = 0.001865 mol / 0.250 L = 0.00746 M

Hence,

M1 = 0.00746 M

V1 = 250 mL

M2 = 0.160 M

V2 = ?

V2 = M1V1 / M2

V2 = 0.00746 M × 250 mL / 0.160 M

V2 = 11.6 mL

Hence the volume of NaOH is 11.6 mL

4 0

3 years ago