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Tpy6a [65]
3 years ago
8

3 Consider the reaction :

Chemistry
1 answer:
ss7ja [257]3 years ago
7 0

Answer:

(a) The rate at which ammonia being formed = 0.0493 M/s

(b) The rate at which molecular nitrogen reacting = 0.0247 M/s

Explanation:

N_{2}+3H_{2}\longrightarrow2NH_{3}

The rate at which molecular hydrogen is reacting = \frac{d}{dt}[H_{2}]=0.074\:M/s

The rate of the above reaction can be expressed as:

rate=-\frac{d}{dt}[N_{2}]=-\frac{1}{3} \frac{d}{dt}[H_{2}]=\frac{1}{2}\frac{d}{dt}[NH_{3}]

(a) \frac{d}{dt}[NH_{3}]=\frac{2}{3}(0.074)=0.0493

The rate at which ammonia being formed = 0.0493 M/s

(b) -\frac{d}{dt}[N_{2}]=\frac{1}{3}(0.074)=0.0247

The rate at which molecular nitrogen reacting = 0.0247 M/s

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