1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
QveST [7]
3 years ago
5

Blackie, a cat whose mass is 6-kg, is napping on top of the refrigerator when he rolls over and fall. Blackie has a KE of 90-J j

ust before he lands on his feet on the floor.
How tall is the refrigerator?
Physics
1 answer:
Anon25 [30]3 years ago
4 0

To answer this question, you need to understand the law of conservation of energy. Essentially, the law states that energy cannot be created or destroyed; it is always conserved.

Knowing this law, how can we answer this question? Well, let's look at what the question tells us. We know that Blackie was initially at the top of a refrigerator before rolling over and falling to the ground. At ground level, he only has Kinetic energy when he lands. Since we know that he started at the top of the fridge, we know that Blackie started off with potential gravitational energy.

That would make sense, right? Written out as an equation, it'd be:

U_{g} = K_{E}

This follows the law of conservation of energy, as all the potential gravitational energy is converted into Kinetic energy.

Now, we know what energies are converted. What can we do with it? Recall the equation of potential gravitational energy:

U_{g} = F_{g}∆H

U_{g} = mg∆H

Do you see it now? ∆H is the distance that Blackie falls, and since Blackie jumps from the fridge to the ground, ∆H must be the height of the fridge!

Let's start solving for ∆H:

U_{g} = K_{E}

<u>Substitute potential gravitational energy with our equation:</u>

mg∆H = K_{E}

<u>We were given the value of Kinetic Energy:</u>

mg∆H = 90

<u>Isolate ∆H by dividing both sides by mg:</u>

∆H = \frac{90}{mg}

<u>Input values for 'm' and 'g' (m is the mass of Blackie and g is Earth's acceleration)</u>

∆H = \frac{90}{6*9.80}

∆H = \frac{90}{58.8}

∆H = 1.53

<u>The refrigerator is 1.53 meters tall.</u>

<em></em>

And that's it! Let me know if you need me to explain anything I did here.

- breezyツ

You might be interested in
Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. The best type of gr
lara31 [8.8K]

Answer:

B line graph

Explanation:

sorry if I am wrong

7 0
3 years ago
Read 2 more answers
A projectile is launched at ground level with an initial speed of 54.5 m/s at an angle of 35.0° above the horizontal. It strikes
Alchen [17]
<h2>Answer: x=125m, y=48.308m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which we have two components: x-component and y-component. Being their main equations to find the position as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=54.5m/s is the projectile's initial speed

\theta=35\° is the angle

t=2.80s is the time since the projectile is launched until it strikes the target

x  is the final horizontal position of the projectile (the value we want to find)

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=0  is the initial height of the projectile (we are told it  was launched at ground level)

y  is the final height of the projectile (the value we want to find)

g=9.8m/s^{2}  is the acceleration due gravity

Having this clear, let's begin with x (1):

x=(54.5m/s)cos(35\°)(2.8s)   (3)

x=125m   (4)  This is the horizontal final position of the projectile

For y (2):

y=0+(54.5m/s)sin(35\°)(2.8s)-\frac{(9.8m/s^{2})(2.8s)^{2}}{2}   (5)

y=48.308m   (6)  This is the vertical final position of the projectile

4 0
3 years ago
An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?
Scorpion4ik [409]

Answer:

80 ft/s

Explanation:

Use III equation of motion

V^2 = U^2 + 2g h

Here, U = 0, g = 32 ft/s^2, h = 100 ft

V^2 = 0 + 2 × 32 ×100

V^2 = 6400

V = 80 ft/s

8 0
3 years ago
A photovoltaic panel of dimension 2 m × 4 m is installed on the roof of a home. The panel is irradiated with a solar flux of GS
Flura [38]

Answer:

(a) the electrical power generated for still summer day is 1013.032 W

(b)the electrical power generated for a breezy winter day is 1270.763 W

Explanation:

Given;

Area of panel = 2 m × 4 m, = 8m²

solar flux  GS = 700 W/m²

absorptivity of the panel, αS = 0.83

efficiency of conversion, η = P/αSGSA = 0.553 − 0.001 K⁻¹ Tp

panel emissivity , ε = 0.90

Apply energy balance equation to determine he electrical power generated;  

transferred energy + generated energy = 0

(radiation + convection) +  generated energy = 0

[\alpha_sG_s-\epsilon \alpha(T_p^4-T_s^4)]-h(T_p-T_\infty) - \eta \alpha_s G_s = 0

[\alpha_sG_s-\epsilon \alpha(T_p^4-T_s^4)]-h(T_p-T_\infty) - (0.553-0.001T_p)\alpha_s G_s

(a) the electrical power generated for still summer day

T_s = T_{\infty} = 35 ^oC = 308 \ k

[0.83*700-0.9*5.67*10^{-8}(T_p_1^4-308^4)]-10(T_p_1-308) - (0.553-0.001T_p_1)0.83*700 = 0\\\\3798.94-5.103*10^{-8}T_p_1^4 - 9.419T_p_1 = 0\\\\Apply \  \ iteration \ method \ to \ solve \ for \ T_p_1\\\\T_p_1 = 335.05 \ k

P = \eta \alpha_s G_s A = (0.553-0.001 T_p_1)\alpha_s G_s A \\\\P = (0.553-0.001 *335.05)0.83*700*8 \\\\P = 1013.032 \ W

(b)the electrical power generated for a breezy winter day

T_s = T_{\infty} = -15 ^oC = 258 \ k

[0.83*700-0.9*5.67*10^{-8}(T_p_2^4-258^4)]-10(T_p_2-258) - (0.553-0.001T_p_2)0.83*700 = 0\\\\8225.81-5.103*10^{-8}T_p_2^4 - 29.419T_p_2 = 0\\\\Apply \  \ iteration \ method \ to \ solve \ for \ T_p_2\\\\T_p_2 = 279.6 \ k

P = \eta \alpha_s G_s A = (0.553-0.001 T_p_2)\alpha_s G_s A \\\\P = (0.553-0.001 *279.6)0.83*700*8 \\\\P = 1270.763 \ W

3 0
3 years ago
Lake Preston's latitude is about 44.4 degrees north of the equator. Which global wind belt are
Serggg [28]

Answer:

Idk

Explanation:

Idk

5 0
3 years ago
Other questions:
  • If you are in an airplane. you look out the window and the clouds appear to be moving. what is your frame of reference?
    7·1 answer
  • PLEASE HELP I NEED IT RIGHT NOW
    13·2 answers
  • Consider an electron that is 10−10 m from an alpha particle
    6·1 answer
  • Two particles A and B start from rest at the origin x = 0 [ft] and move along a straight line such that a = (613) Ift/s) and ag
    8·1 answer
  • How many protons are found in 1 c positive
    11·1 answer
  • A 70-Ω electrical appliance and a 100-Ω electrical appliance are plugged into the outlets of a house. By what factor will the po
    8·1 answer
  • Electrons in the beam are accelerated by the ____ fields.
    15·1 answer
  • What is mummification?
    8·2 answers
  • Becky wanted to figure out what type of liquid worked best for growing beans . She wanted one with coca-cola ,one with lemonade,
    8·1 answer
  • The response of an object to the gravity is called ____
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!