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Nataliya [291]
3 years ago
10

An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?

Physics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

80 ft/s

Explanation:

Use III equation of motion

V^2 = U^2 + 2g h

Here, U = 0, g = 32 ft/s^2, h = 100 ft

V^2 = 0 + 2 × 32 ×100

V^2 = 6400

V = 80 ft/s

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          P_int1 < P_ext1

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en promedio la presión disminuye con la altura  en 0,029 atm cada 250 m

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        P_int2 >P_ext2

Traslate

This exercise is related to fluid mechanics, let's use the expression for pressure

       P = ρ g h

In the case of the balloon, let's use the pressure on the extreme wall, let's call P the pressure for the gas inside and P_ext the atmospheric pressure of the place

        when the value is filled in a low-lying city the atmospheric pressure is higher

          P_int1 <P_ext1

therefore the wall of the ball does not remain rigid.

When the ball is transferred to a city with higher altitude above sea level, the external pressure decreases

       P_ext2 = ρ g h <P_ext1

on average the pressure decreases with height by 0.029 atm every 250 m

therefore as balloon is rigid the amount of gas is constant inside the interior pressure of the balloon is constant and in these cities it becomes equal to or slightly higher than atmospheric pressure, therefore the wall of the

        Pint 2> Pe

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