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nalin [4]
2 years ago
8

A 70-Ω electrical appliance and a 100-Ω electrical appliance are plugged into the outlets of a house. By what factor will the po

wer used change if an additional 130-Ω electrical device is plugged in?
Physics
1 answer:
lukranit [14]2 years ago
8 0

Answer:

For an additional 130-Ω electrical device, the power used will change by a factor of 0.77.

Explanation:

Power is given as;

P = I²R

Where;

P is the power used due to resistance of the electrical appliance

I is the current passing through the appliance

R is the resistance offered by the appliance

For 70-Ω electrical appliance and  100-Ω electrical appliance, the total power used is;

P = 70I² + 100 I² =  (170I²) W

for an additional 130-Ω electrical device, the new the total power used is;

P = 130I² +  (170I²)  = (300 I²)W

Change \ in \ power \ used = \frac{I^2(300-170)}{I^2(170)} =0.77

Therefore, for an additional 130-Ω electrical device, the power used will change by a factor of 0.77.

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An electron moving in the direction of the +x-axis enters a magnetic field. If the electron experiences a magnetic deflection in
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Answer:

<em>-z axis</em>

Explanation:

According to the left hand rule for an electron in a magnetic field, hold the thumb of the left hand at a right angle to the rest of the fingers, and the rest of the fingers parallel to one another. If the thumb represents the motion of the electron, and the other fingers represent the direction of the field, then the palm will push in the direction of the force on the electron. In this case, the left hand will be held out with the thumb pointing to the right (+x axis), and the palm facing your body (-y axis). The magnetic field indicated by the other fingers will point down in the the -z axis.

5 0
2 years ago
Is it possible to have negative velocity but positive acceleration? If so, what would this mean?
dusya [7]

Observe that the object below moves in the negative direction with a changing velocity. An object which moves in the negative direction has a negative velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion (in this case, a positive acceleration). The dot diagram shows that each consecutive dot is not the same distance apart (i.e., a changing velocity). The position-time graph shows that the slope is changing (meaning a changing velocity) and negative (meaning a negative velocity). The velocity-time graph shows a line with a positive (upward) slope (meaning that there is a positive acceleration); the line is located in the negative region of the graph (corresponding to a negative velocity). The acceleration-time graph shows a horizontal line in the positive region of the graph (meaning a positive acceleration).

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4 0
2 years ago
An ordinary egg can be approximated as a 5.5-cm diameter sphere. The egg is initially at a uniform temperature of 8°C and is dro
kupik [55]

Answer:

a) Q_{in} = 13.742\,kW, b) \Delta S = 370.15\,\frac{kJ}{K}

Explanation:

a) The heat transfered to the egg is computed by the First Law of Thermodynamics:

Q_{in} +U_{sys,1} - U_{sys,2} = 0

Q_{in} = U_{sys,2} - U_{sys,1}

Q_{in} = \rho_{egg}\cdot \left(\frac{4\pi}{3}\cdot r^{3}\right)\cdot c \cdot (T_{2}-T_{1})

Q_{in} = \left(1020\,\frac{kg}{m^{3}}\right)\cdot \left(\frac{4\pi}{3}\right)\cdot (0.025\,m)^{3}\cdot \left(3.32\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (70\,^{\textdegree}C - 8\,^{\textdegree}C)

Q_{in} = 13.742\,kW

b) The amount of entropy generation is determined by the Second Law of Thermodynamics:

\Delta S = \frac{Q_{in}}{T_{in}}

\Delta S = \frac{13.742\,kJ}{370.15\,K}

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3 0
3 years ago
If the caffeine concentration in a particular brand of soda is 2.97 mg/oz, 2.97 mg/oz, drinking how many cans of soda would be l
Ray Of Light [21]

Explanation:

The given data is as follows.

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     Number of oz in a can = 12 oz

Therefore, the concentration of caffeine in one can is calculated as follows.

                 = (12 \times 2.97) mg

                 = 35.64 mg

                 = 35.64 \times 10^{-3} g

Since, it is given that lethal dose is 10.0 g. Hence, number of cans are calculated as follows.

     No. of cans = \frac{\text{Lethal dose}}{\text{concentration in one can}}

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                         = 281 (approx)

Thus, we can conclude that 281 cans of soda would be lethal.

5 0
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