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Novosadov [1.4K]
3 years ago
7

Lake Preston's latitude is about 44.4 degrees north of the equator. Which global wind belt are

Physics
1 answer:
Serggg [28]3 years ago
5 0

Answer:

Idk

Explanation:

Idk

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Ocean waves are traveling to the east at 4.9 m/s with a distance of 23 m between crests. (b) With what frequency do the waves hi
ser-zykov [4K]

Answer:

0.26086 Hz

Explanation:

solution:

The relative speed of the wave is:

v = 4.9+1.1 = 6 m/s

the frequency is:

f = v/λ

 = 6/23

 = 0.26086 Hz

6 0
4 years ago
A bus travels with an average velocity of 60 km per hour. how long does it take to cover a distance of 500km?
sergeinik [125]
V = 60km/h
S=500km
t = ?
v = S/t
t = S/v
t = 500km / 60 km/h
t ≈ 8,33 h
6 0
4 years ago
A ball is thrown horizontally from the top of
Serhud [2]

Answer:

52.38 m/s

Explanation:

5 0
3 years ago
Read 2 more answers
What is the order of magnitude of the distance of Sun to nearest star in meters?
neonofarm [45]

Answer:

Approximating the Milky Way as a disk and using the density in the solar neighborhood, there are about 100 billion stars in the Milky Way.

Explanation:

Since we are making an order of magnitude estimate, we will make a series of simplifying assumptions to get an answer that is roughly right.

Let's model the Milky Way galaxy as a disk.

The volume of a disk is:

V

=

π

⋅

r

2

⋅

h

Plugging in our numbers (and assuming that

π

≈

3

)

V

=

π

⋅

(

10

21

m

)

2

⋅

(

10

19

m

)

V

=

3

×

10

61

m

3

Is the approximate volume of the Milky Way.

Now, all we need to do is find how many stars per cubic meter (

ρ

) are in the Milky Way and we can find the total number of stars.

Let's look at the neighborhood around the Sun. We know that in a sphere with a radius of

4

×

10

16

m there is exactly one star (the Sun), after that you hit other stars. We can use that to estimate a rough density for the Milky Way.

ρ

=

n

V

Using the volume of a sphere

V

=

4

3

π

r

3

ρ

=

1

4

3

π

(

4

×

10

16

m

)

3

ρ

=

1

256

10

−

48

stars /

m

3

Going back to the density equation:

ρ

=

n

V

n

=

ρ

V

Plugging in the density of the solar neighborhood and the volume of the Milky Way:

n

=

(

1

256

10

−

48

m

−

3

)

⋅

(

3

×

10

61

m

3

)

n

=

3

256

10

13

n

=

1

×

10

11

stars (or 100 billion stars)

Is this reasonable? Other estimates say that there are are 100-400 billion stars in the Milky Way. This is exactly what we found.

4 0
3 years ago
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Why is silicon needed in solar panels?
kodGreya [7K]
Hi, silicon is essential in solar panels because, silicon is a semiconductor material (meaning a solid substance that has a conductivity of an insulator and is an essential component of most electric circuits ) now, when dipped with impurities such as gallium and arsenic it has the ability to capture the suns energy and convert to electricity. hope this is helpful if it is than put a thank you plz.
4 0
3 years ago
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