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sp2606 [1]
3 years ago
5

Need Help with Polynomials

Mathematics
1 answer:
Elena L [17]3 years ago
6 0

Answer:

1. yes all yes

Step-by-step explanation:

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Just need the answer. it was "Check all that apply." at the end.
lianna [129]

Billy, let's recall what a linear pair of angles is:

• They are formed when two lines intersect.

,

• Two angles are said to be linear if they are adjacent angles formed by two intersecting lines.

,

• The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

Upon saying that we have that:

• CAD and DAE are linear pairs

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• CAD and CAB are linear pairs

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• DAE and BAE are linear pairs

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• DAE and DAC are linear pairs

Now, you are ready to select all the options that actually apply.

3 0
2 years ago
Graph the equation using the slope and y-intercept<br> y = -x + 3
docker41 [41]

Answer:

Slope: −1

y-intercept: (0,3)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The table shows the temperature (y) at different altitudes (x).
Shtirlitz [24]

Answer/Step-by-step explanation:

2. Using two pairs of values, (0, 59) and (2,000, 51),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{51 - 59}{2,000 - 0} = \frac{-8}{2,000} = -\frac{1}{250}

3. The y-intercept is the value of y when x = 0. Thus, x = 0, when y = 59. Therefore,

y-intercept (b) = 59

4. To write an equation in slope-intercept form, simply substitute m = -¹/250, and b = 59, in y = mx + b

✅y = -\frac{1}{250}x + 59

5. Substitute x = 5,000 in y = -\frac{1}{250}x + 59.

y = -\frac{1}{250}(5,000) + 59

y = -20 + 59

y = 39

At an altitude of 5,000 ft, temperature would be 39°F

3 0
3 years ago
A.28.0<br><br> B.19.8<br> C.14.0<br><br> D.3.7
Lady_Fox [76]
Sin(angle) = opposite leg / hypotenuse

Sin(45) = Opposite leg / 28

Opposite Leg = 28 * Sin(45)

Opposite Leg = 14 SQRT(2) = 19.8


7 0
4 years ago
Find a common denominator for the pair of fractions.​ Then, write equivalent fractions with the common denominator.
DerKrebs [107]
4/12? It may be wrong, not sure
3 0
3 years ago
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