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3 years ago

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2 answers:

8 0

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shutvik [7]3 years ago

6 0

Answer:

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The standard form of the equation of a circle with center (h, k) and radius r is __________________.

Naddika [18.5K]

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}$

5 0

3 years ago

Mira has breakfast at a restaurant. She leaves a 20% tip of $1.80.

Anvisha [2.4K]

Answer: $9.00

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4 0

3 years ago

The Foster Family, and the Tyson family, and the O'Jennie family, got together for Thanksgiving, and had a large turkey that cou

sasho [114]

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5 0

3 years ago

Expression of "Eight less than half the sum of 4 and k” into symbol

jolli1 [7]

Answer:

$\frac{4+k}{2} -8$

Step-by-step explanation:

We're going to have to work backwards.

The sum of 4 and k is $4+k$ .

Half is simply that divided by 2.

$\frac{4+k}{2}$

Now, we'll subtract 8 from it.

$\frac{4+k}{2} -8$

Bam!

7 0

3 years ago

Someone please let me know the answer

erastova [34]

Answer:

The answer is 30°

Step-by-step explanation:

$when \: \: \sqrt{3} \sin( \alpha ) - \cos( \alpha ) = 0 \\ \sqrt{3} \sin( \alpha ) = \cos( \alpha ) \\ multiply \: by \: \frac{1}{ \sqrt{3} \cos( \alpha ) } \\ then \\ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \frac{1}{ \sqrt{3} } \\ \tan( \alpha ) = \frac{1}{ \sqrt{3} } \\ then \: \alpha = 30$

3 0

3 years ago