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tekilochka [14]
3 years ago
12

A train travels 60 miles per hour for 3 hours and then 45 miles per hour for 2 hours. What is the train’s average speed in miles

per hour during the 5‑hour period?
Physics
2 answers:
eimsori [14]3 years ago
5 0

Answer:

Explanation:

Average speed is given by

Total distance/ total time taken

So we need to know the distance in the first travel

Then

First part

Speed=60miles/hour

Time 3hours

Distance = speed × time

Distance = 60×3

Distance = 180 miles

Second part

Speed 45mile/hour

And time is 2hours

Distance = speed × time

Distance = 45× 2

Distance = 90miles

So total distance travelled for both cases is 90+180=270miles

And total time is 5hours

Then,

Average speed = total distance/total time

A.S=270/5

A.S= 54miles/hour

dedylja [7]3 years ago
3 0

Answer:

ah

Explanation:

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Answer:

a.I=981.34 N*s

b.v_f=3.96 m/s

c.v_{f1}=3.63m/s

d.y_f=0.673m

Explanation:

Given: m=67kg, h=0.720m, 0

a.

I=\int\limits^{t_1}_{t_2} {F(t)} \, dt

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c.

I_{total}=p_f

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Solve to vf

v_{f1}=3.63m/s

d.

v_f^2=v_i^2+2*a*y_f'

y_f'=v_i/2*a =(3.63m/s)^2/2*9.8m/s^2

y_f=0.673m

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