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3 years ago

Describe the total momentum of billiard balls before and after the cue ball collides with another ball.

Physics

2 answers:

Semmy [17]3 years ago

7 0

Answer:

The Total Momentum before and after collision remains the same.

Explanation:

Note that the balls have the same masses.

A moving cue ball has an initial momentum. After every collision with another stationary ball, the momentum, which is the product of their mass and velocity, of the balls is conserved. This simply means that the total momentum before the collision is the same as the total momentum after the collision.

This also means that the energy must be conserved as well. The balls cannot fling away from each other with more energy than you give them.

dolphi86 [110]3 years ago

6 0

Answer:

Total momentum is conserved before and after collusion and it's elastic.

Explanation:

For two colliding balls, the general vector equation for conservation of linear momentum is giving as

Ma*V1a = Ma*V2a + Mb*V2b

Where Ma=mass of que ball = Mb = mass of billiard ball so therefore

V1a= velocity of que ball before impact, V2a = velocity of que ball after impact, V2b = velocity of billiard ball after impact.

So therefore:

V1a = V2a + V2b

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It is known that birds can detect the earth's magnetic field, but the mechanism of how they do this is not known. It has been su

san4es73 [151]

Answer:

$EMF = 5.01 \times 10^{-4} Volts$

Explanation:

Here we know that the EMF induced in this Field is given as

$EMF = vBL$

here B = perpendicular component of magnetic field

v = speed of the bird

L = length of the wings

now we have

$B = 5\times 10^{-5} sin40$

$v = 13 m/s$

$L = 1.2 m$

now we have

$EMF = (13)(3.21 \times 10^{-5})(1.2)$

$EMF = 5.01 \times 10^{-4} Volts$

8 0

3 years ago

A child goes down the slide,starting from rest. If the length of the slide is 2m and it takes the child 3 seconds to go down the

lapo4ka [179]

Answer:

$0.44 m/s^2$

Explanation:

We have the following data:

- distance covered by the child: d = 2 m (length of the slide)

- time taken to cover this distance: t = 3 s

- initial velocity of the child: 0 m/s (he starts from rest)

So we can find the acceleration by using the equation:

$d=ut+\frac{1}{2}at^2$

Where a is the acceleration.

Substituting the values and solving for a,

$a=\frac{2d}{t^2}=\frac{2(2)}{3^2}=0.44 m/s^2$

3 0

3 years ago

Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. There is now a nega

devlian [24]

Answer: its negative

Explanation: becase it is

5 0

3 years ago

Why is the current atomic model called the "electron could model"

vlada-n [284]

The diagram is showing a 3d model of an atom, with all of the electrons demonstrated in a rounded shape, which resembles a cloud, thus being called an electron cloud.

8 0

3 years ago

Calculate the total energy of 4.0 kg object moving horizontally at 20 m/s 50 meters above the surface.

Serhud [2]

Answer:

Correct answer: E total = 2,800 J

Explanation:

Given:

m = 4 kg the mass of the object

V = 20 m/s the speed (velocity) of the object

H = 50 m the height of the object above the surface

E total = ? J

The total energy of an object is equal to the sum of potential and kinetic energy

E total = Ep + Ek

Ep = m g H we take g = 10 m/s²

Ep = 4 · 10 · 50 = 2,000 J

Ek = m V² / 2

Ek = 4 · 20² / 2 = 2 · 400 = 800 J

E total = 2,000 + 800 = 2,800 J

E total = 2,800 J

God is with you!!!

4 0

3 years ago