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qwelly [4]
3 years ago
7

a 3.2 kg durian fruit is pushed across the table.If the acceleration of the durian is 3.1 m/s/s to the right,what is the net for

ce exerted on the fruit?(Fnet=ma)​
Physics
2 answers:
Gala2k [10]3 years ago
4 0

Answer:

<h2>9.92 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.2 × 3.1

We have the final answer as

<h3>9.92 N</h3>

Hope this helps you

kolezko [41]3 years ago
3 0

Answer:

9.92

Hope I helped

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