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qwelly [4]
3 years ago
7

a 3.2 kg durian fruit is pushed across the table.If the acceleration of the durian is 3.1 m/s/s to the right,what is the net for

ce exerted on the fruit?(Fnet=ma)​
Physics
2 answers:
Gala2k [10]3 years ago
4 0

Answer:

<h2>9.92 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.2 × 3.1

We have the final answer as

<h3>9.92 N</h3>

Hope this helps you

kolezko [41]3 years ago
3 0

Answer:

9.92

Hope I helped

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The probability of getting 4 is 1

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A viscous liquid is sheared between two parallel disks of radius �, one of which rotates with angular speed Ω, while the other i
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Answer:

Upper disk rotates at a constant angular velocity. The velocity at any height from stationery disk, say at x metres

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U_o=r\omega (\frac {x}{h})

The radial component of velocity is given as

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The z component of velocity is also given as  

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3 years ago
4. A cinder block is sitting on a platform 20 m high. It has a mass of 4 kg. The block has energy. Calculate it.
zavuch27 [327]

Answer:

Explanation:

Since the block is at rest in an elevated position, we can assume that it only has potential energy.

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Plug in known variables....

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4 0
2 years ago
How does the molecular structure of a water molecule affect its polarity?
MA_775_DIABLO [31]

Answer:

The polarity of water molecules means that molecules of water will stick to each other like when unlike charges attracts. This is called hydrogen bonding.

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3 years ago
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A flat uniform circular disk (r= 2.00m,
dusya [7]

Incomplete question.The Complete question is here

A flat uniform circular disk (radius = 2.00 m, mass = 1.00 ✕ 102 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a friction less axis perpendicular to the center of the disk. A 40.0-kg person, standing 1.25 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.00 m/s relative to the ground.

a.) Find the resulting angular speed of the disk (in rad/s) and describe the direction of the rotation.

b.) Determine the time it takes for a spot marking the starting point to pass again beneath the runner's feet.

Answer:

(a)ω = 1 rad/s

(b)t = 2.41 s

Explanation:

(a) initial angular momentum = final angular momentum  

0 = L for disk + L............... for runner

0 = Iω² - mv²r ...................they're opposite in direction

0 = (MR²/2)(ω²) - mv²r ................where is ω is angular speed which is required in part (a) of question

0 = [(1.00×10²kg)(2.00 m)² / 2](ω²) - (40.0 kg)(2.00 m/s)²(1.25 m)

0=200ω²-200

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ω = 1 rad/s

b.)

lets assume the "starting point" is a point marked on the disk.

The person's angular speed is  

v/r = (2.00 m/s) / (1.25 m) = 1.6 rad/s

As the person and the disk are moving in opposite directions, the person will run part of a revolution and the turning disk would complete the whole revolution.

(angle) + (angle disk turns) = 2π

(1.6 rad/s)(t) + ωt = 2π

t[1.6 rad/s + 1 rad/s] = 2π

t = 2.41 s

6 0
3 years ago
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