Answer:
The observer detects light of wavelength is 115 nm.
(b) is correct option
Explanation:
Given that,
Wavelength of source = 500 nm
Velocity = 0.90 c
We need to calculate the wavelength of observer
Using Doppler effect
Where,
Hence, The observer detects light of wavelength is 115 nm.
The frequency of the electromagnetic wave is 9.55 × 1014 Hz and it is classified as ultraviolet.
<h3>What is meant by electromagnetic waves?</h3>Electromagnetic waves are forms of energy that are invisible and travel throughout the universe. However, some of the effects of this energy are visible. The light that we see is a component of the electromagnetic spectrum.
Electromagnetic waves, or EM waves, are produced by vibrations between an electric field and a magnetic field. In other words, electromagnetic waves are made up of oscillating magnetic and electric fields.
<h3>How do you calculate the speed of an electromagnetic wave?</h3>
The wavelength and frequency of any periodic wave are used to calculate its speed. v = λf.
In free space, the speed of any electromagnetic wave is equal to the speed of light, c = 3 108 m/s.
The frequency of the electromagnetic wave is 9.55 × 1014 Hz and it is classified as ultraviolet.
To learn more about electromagnetic wave refer to:
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The new velocity after 4 s is 40 m/s
The height of the spaceship above the ground after 5 seconds is 1,127.5 m
The given parameters for the first question;
The new velocity after 4 s is calculated as;
v = u + at
v = 76 + (-9)(4)
v = 76 - 36
v = 40 m/s
(5)
The given parameters;
The height of the spaceship above the ground after 5 seconds is calculated as;
Learn more here: brainly.com/question/24527971