Question

a 3.2 kg durian fruit is pushed across the table.If the acceleration of the durian is 3.1 m/s/s to the right,what is the net force exerted on the fruit?(Fnet=ma)​

Answer 1

Answer:

9.92 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.2 × 3.1

We have the final answer as

9.92 N

Hope this helps you

Answer 2

Answer:

9.92

Hope I helped