A 6 N force and a 15 N force act on an object. The moment arm of the 6 N force is 0.4 m. If the 15 N 20. force provides 5 times
the torque of the 6 N force, what is its moment arm?
1 answer:
Answer:
0.8 m
Explanation:
For "6 N" force :
F = magnitude of the force = 6 N
r = moment arm = 0.4 m
Torque due to "6 N" force is given as
τ = r F
τ = (0.4) (6)
τ = 2.4 Nm
For " 15 N" force :
F' = magnitude of the force = 15 N
r' = moment arm = ?
τ' = Torque = 5 τ = 5 x 2.4 = 12 Nm
Torque due to "15 N" force is given as
τ' = r' F'
12 = r' (15)
r' = 0.8 m
So the moment arm for "15 N" force is 0.8 m
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