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Lelu [443]
3 years ago
9

If a boy with 50kg run in 3m/s what is his velocity

Physics
2 answers:
Thepotemich [5.8K]3 years ago
7 0

need to know direction. mag of vel = speed = 3m/s

stepladder [879]3 years ago
6 0

His velocity is 3 m/s in the direction in which he is running in. which.

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A solar flare is a sudden, rapid, and intense change in the brightness of the sun. Which of these is most
nikdorinn [45]

Answer:

electronic communications may be disrupted

Explanation:

Solar Flares: They occur when the magnetic field lines carrying charged particle entangle and reorganize over the photosphere of the Sun. In these flares charged particles leave the surface of the Sun to travel outwards.

If these flares are directed towards Earth, they will interact with anything related to electricity and magnetism. Out of the given options third option is correct as the electronic communication will be disrupted. If the flares are strong a complete power blackout may occur and that would disrupt all the communication channel and power transmission. Such events have occurred in the past as well.

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Upper section of the lithosphere
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On the Newtonian theory of gravity, gravitation affects anything with mass. Assuming that none of the answer choices is the only thing that exists in the universe, all of the answer choices are subject to the law of universal gravitation (hence “universal”).

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3 0
3 years ago
A 0.106-A current is charging a capacitor that has square plates 6.00 cm on each side. The plate separation is 4.00 mm. (a) Find
FrozenT [24]

Answer:

The time rate of change of flux is 1.34 \times 10^{10} \frac{V}{s}

Explanation:

Given :

Current I = 0.106 A

Area of plate A = 36 \times 10^{-4} m^{2}

Plate separation d = 4 \times 10^{-3} m

(A)

First find the capacitance of capacitor,

   C = \frac{\epsilon _{o} A }{d}

Where \epsilon _{o} = 8.85 \times 10^{-12}

   C = \frac{8.85 \times 10^{-12 } \times 36 \times 10^{-4}  }{4 \times 10^{-3} }

   C = 7.9 \times 10^{-12} F

But   C = \frac{Q}{V}

Where Q = It

  C = \frac{It}{V}

  V = \frac{It}{C}

Now differentiate above equation wrt. time,

  \frac{dV}{dt} = \frac{I}{C}

       = \frac{0.106}{7.9 \times 10^{-12} }

       = 1.34 \times 10^{10} \frac{V}{s}

Therefore, the time rate of change of flux is 1.34 \times 10^{10} \frac{V}{s}

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