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3 years ago

If a boy with 50kg run in 3m/s what is his velocity

Physics

2 answers:

Thepotemich [5.8K]3 years ago

7 0

need to know direction. mag of vel = speed = 3m/s

stepladder [879]3 years ago

6 0

His velocity is 3 m/s in the direction in which he is running in. which.

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An airplane flies with a constant speed of 560 miles per hour. How far can it travel in 1 1/2 hours?

Alik [6]

You would multiply the speed by the time. So the answer would be 840 miles.

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3 years ago

50 cm to mA flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform ma

sukhopar [10]

Answer:

0.025 A

Explanation:

A = 50 cm^2 = 50 x 10^-4 m^2

B2 = 6 T, B1 = 2 T

db = 6 - 2 = 4 T

dt = 2 s

R = 0.4 ohm

Let i be the magnitude of induced current and e be the induced emf.

According to the Faraday's law of electromagnetic induction

e = dФ / dt

e = A dB / dt

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2 years ago

A mineral's chemical composition and crystal structure help determine it's ___________.

AnnyKZ [126]

Hiya!

The answer to your question is B.

Physical Properties.

~Hope this helps~

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3 years ago

A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr

Zinaida [17]

Answer:

The initial speed of bullet is "164 m/s".

Explanation:

The given values are:

mass of bullet,

$m'=9.00 \ g$

or,

$=0.009 \ kg$

mass of wooden block,

$m=1.20 \ kg$

speed,

$s=0.390 \ m$

Coefficient of kinetic friction,

$\mu=0.20$

As we know,

The Kinematic equation is:

⇒ $v^2=u^2+2as$

then,

Initial velocity will be:

⇒ $u=v^2-2as$

$=v^2-2 \mu gs$

On substituting the given values, we get

⇒ $u=\sqrt{0-2\times 0.20\times 9.8\times 0.390}$

$=\sqrt{-1.5288}$

$=1.23 \ m/s$

As we know,

The conservation of momentum is:

⇒ $mu=m'u'$

or,

⇒ Initial speed, $u'=\frac{mu}{m'}$

On substituting the values, we get

⇒ $=\frac{1.20\times 1.23}{0.009}$

⇒ $=\frac{1.476}{0.009}$

⇒ $=164 \ m/s$

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2 years ago

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ankoles [38]

The human eye is not capable of seeing radiation wavelengths outside the visible Spectrum, i hope this answers your question :)

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2 years ago