Answer:
Explanation: RADIUS OF EARTH = 6400X1000m =
ACC DUE GRAVITY ABOVE SURFACE OF EARTH = g' =2.45 m/s^2
ACC DUE GRAVITY ON SURFACE OF EARTH =g= 9.8 m/s^2
A/C TO FORmULA
g'/g=1-2h/Re
g'/g +2h/Re = 1
2h/Re =1- g'/g
2h= (1- g'/g)Re
2h=(1-2.45 /9.8)
6400X1000
2h = (0.75)6400X1000
2h = 4800000
h= 2400000
m
Answer:
Distancia = 42.5 metros
Explanation:
Dados los siguientes datos;
Velocidad del sonido = 340 m/s
Tiempo = 8 segundos
Para encontrar la distancia desde la que se escuchó el sonido;
Distancia = velocidad/tiempo
Sustituyendo en la fórmula, tenemos;
Distancia = 340/8
Distancia = 42.5 metros
You must first convert minutes to seconds so 10*60=600
Then multiply the number of seconds by the speed so 600*2=1200 m
Light of the moon is from the light of the sun. So if you're in a certain area where the angle from where your seeing the moon happens to be where the sun's light shines throughout that area. You see a full moon. It's like shining a flashlight on a ball. You move around it and you see half of the light, quarter of the light or even none at all.
<span>5 seconds expired during the deceleration.
Top rotated 45 radians during these 5 seconds.
First, calculate the chance in velocity, by subtracting the initial velocity from the final velocity. So
6 rad/s - 12 rad/s = -6 rad/s
So we lost a total of 6 rad/s. Divide that by the deceleration to give the number of seconds. So
-6 rad/s / -1.2 rad/s^2 = 5 s
So it takes 5 seconds for the deceleration to happen.
The equation that expresses the number of radians performed under constant deceleration with an initial velocity is
d = VT + 0.5 AT^2
where
d = distance
V = initial velocity
T = time
A = acceleration
Substituting the known values gives.
d = VT + 0.5 AT^2
d = 12 rad/s * 5s + 0.5 * -1.2 rad/s^2 (5s)^2
d = 60 rad -0.6 rad/s^2 *25s^2
d = 60 rad -15 rad
d = 45 rad
So the top rotated 45 radians while decelerating from 12 rad/s to 6 rad/s</span>
