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2 years ago

How many solutions does 6x−1=34−x have

Mathematics

1 answer:

aleksley [76]2 years ago

4 0

Step-by-step explanation:

6x+x=34+1

7x=35

x=35/7

x=5

Hence this equation has only one solution

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IN DESPERATE NEED OF HELP!!!! TIMED TEST!!! WILL GIVE BRAINLYEST!! No links or I will report u

ANEK [815]

Answer:

a) Slope is -4/3 y-intercept is 2

b) Slope is 2 y-intercept is -1

Step-by-step explanation:

y=mx+c

m=gradient (or in this case slope)

c=y-intercept

6 0

3 years ago

Which systems of equations intersect at point A in this graph?

abruzzese [7]

Answer:

The point of intersection of the system of equations is:

(x, y) = (-2, 1)

The correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

Step-by-step explanation:

Given the point

A (-2, 1)

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Arrange equation variable for elimination

$\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}$

$y+3x=-5$

$-$

$\underline{y-4x=9}$

$7x=-14$

so the system of equations becomes

$\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}$

Solve 7x = -14 for x

$7x=-14$

Divide both sides by 7

$\frac{7x}{7}=\frac{-14}{7}$

Simplify

$x = -2$

For y - 4x = 9 plug in x = 2

$y-4\left(-2\right)=9$

$y+4\cdot \:2=9$

$y+8=9$

Subtract 8 from both sides

$y+8-8=9-8$

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) = (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

3 0

2 years ago

this is the rust of the questions please please some one helps me because I really try my best to solve it . thank you

lyudmila [28]

Answer:

x = 24.

r $\ne$ 0.

Step-by-step explanation:

2. The given equation is:

$\frac{1}{2} (x - 4) = \frac{1}{3} x + 2$

a) To eliminate the fractions multiply the equation throughout by the LCM of the denominators of the fraction. In this case, the LCM of (2, 3). The LCM is 6. So, multiply the entire equation by 6.

b) Half of the difference between an integer and 4 equals the sum of one - third of the integer and 2. Find the integer.

c) We have the equation:

$\frac{1}{2} (x - 4) = \frac{1}{3} x + 2$

Multiplying throughout by 6, we get:

$\frac{6}{2}(x - 4) = \frac{6}{3} x + 6(2)$

$\implies 3(x - 4) = 2x + 12$

$\implies 3x - 12 = 2x + 12$

$\implies x = 24$

Therefore, the solution of the equation is 24.

3. The given equation is: $ry + s = tx - m$

To solve for y:

We can rearrange the equation as:

$ry = tx - m - s$

$\implies y = \frac{tx - m - s}{r}$

or, $y = \frac{tx - (m + s)}{r}$

Note that we have to impose a condition on variable $r$ . It would be that $r$ can never be zero. i.e., $r \ne 0$ . Otherwise, the value of $y$ would be undefined.