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marta [7]
2 years ago
9

How many grams of HCl(aq) are required to react completely with 1.25g of Zn(s) to form ZnCl2(aq) and H2

Chemistry
1 answer:
faltersainse [42]2 years ago
8 0

1.39 g HCl

Explanation:

The balanced chemical equation for this reaction is given by

Zn(<em>s</em>) + 2HCl(<em>aq</em>) ---> ZnCl2(<em>aq</em>) + H2(<em>g</em>)

Convert the # of grams of Zn to moles:

1.25 g Zn × (1 mol Zn/65.38 g Zn) = 0.0191 mol Zn

Use the molar ratio to find the # of moles of HCl needed to react completely with the given amount of Zn:

0.0191 mol Zn × (2 mol HCl/1 mol Zn) = 0.0382 mol HCl

Convert this amount to grams:

0.0382 mol HCl × (36.458 g HCl/1 mol HCl) = 1.39 g HCl

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To know more about Copper here:

brainly.com/question/19761029?referrer=searchResults

#SPJ4

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