Answer:
0.4 M
Explanation:
The process that takes place in an aqueous K₂HPO₄ solution is:
First we <u>calculate how many K₂HPO₄ moles are there in 200 mL of a 0.2 M solution</u>:
- 200 mL * 0.2 M = 40 mmol K₂HPO₄
Then we <u>convert K₂HPO₄ moles into K⁺ moles</u>, using the <em>stoichiometric coefficients</em> of the reaction above:
- 40 mmol K₂HPO₄ *
= 80 mmol K⁺
Finally we <em>divide the number of K⁺ moles by the volume</em>, to <u>calculate the molarity</u>:
- 80 mmol K⁺ / 200 mL = 0.4 M
the answer should be a the the question
Answer:
is that chromium on that computer ?
Explanation:
The empirical formula of the compound is C₄H₅O₃.
<u>Explanation</u>:
If hydrogen % = 5.98823, the Sum of C+O = 94.01177% or 47.005885% each
The original mass of 300 g is not important
C = 47.005885 / 12.011 = 3.913569
H = 5.98823 / 1.008 = 5.94070
O = 47.005885 / 15.999 = 2.93805
Divide by the smallest number:
C =1.33
H = 2.022
O = 1
Multiply through by 3
C = 4
H =6
O = 3
The empirical formula of a compound = C₄H₆O₃
Do not be confused by the 300 g. It is totally irrelevant to the question because you are dealing with % amounts. It would only have been of importance if you were given some mass values.
