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bixtya [17]
3 years ago
14

1) Mrs Tan is 43 years old and her daughter is 17 years old. How many years ago was Mrs Tan 3 times as old as her daughter?

Mathematics
1 answer:
Leona [35]3 years ago
8 0

Answer:

No 1

Here,

Let X be age of daughter

and 3X be age of father

Now,x+17+3 = 20 age

and 3x+43-20 = 7point9x

Step-by-step explanation:

So,

20÷7point9 = 2point8 years ago

Hence,

age of father = 48÷2point8 = 21point5 years

age of daughter = 20÷2point8 = 10 years

so, before 2point8 years ago father was as old as his daughter

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7x+2y&gt;-5(-1,1)<br><br> Determine whether the ordered pair is a solution of the linear inequality
boyakko [2]

Answer:

  • No

Step-by-step explanation:

<u>Given inequality:</u>

  • 7x + 2y > - 5

<u>Verify if (-1, 1) is correct:</u>

  • 7(-1) + 2(1) > - 5
  • - 7 + 2 > - 5
  • - 5 > - 5

False inequality, it is not the solution

7 0
2 years ago
Find the derivative of f(x)= e^(4x) + e^-(4x)
ololo11 [35]

Answer:

f'(x)=4e^{4x} -4e^{-4x}

Step-by-step explanation:

To find this derivative, we will need to use the chain rule.

As there is a variable in the exponent we can use this formula:

f'(x)=u'e^u

In this case, u=4x and u=-4x

This means that u'=4 and u'=-4 respectively

This gives us f'(x)=4e^{4x} -4e^{-4x}

4 0
2 years ago
Read 2 more answers
M³×n=189 Find m and n
Flura [38]

Answer:

m=3, n = 7

Step-by-step explanation:

Assuming m and n are integers, the following are the possible values of m and n

Let m = 1, then m³ = 1 and n= 189

If m = 2 we get 8n = 189 and 189/8 is not an integer so m ≠ 2

If m = 3, we get 27n = 189 and n = 189/27 = 7

Any higher integer values of m will not result in n being an integer and I am assuming m > 1 so the correct answer is m=3, n = 7

3 0
1 year ago
Please make this quick
AveGali [126]

Answer:

27

Step-by-step explanation:

3x3+2x9=27

8 0
3 years ago
Use the triangle below to find cos V.
Semenov [28]

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

8 0
2 years ago
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