Answer:
The answer would either be Carbon or Silicon.
Explanation:
Chlorine has a charge -1. It means that X is +2 so that the formula is XCl2. Group 2 is the correct answer.
The correct answer is 1) Ag, Si, I₂
Ag or silver is a metal. Silver is a transition element which lies in the d-block of the periodic table.
Si or silicon is a metalloid. Silicon is a metalloid which lies in the p-block of the periodic table.
I₂ or iodine is a nonmetal. Iodine is a halogen which lies in group 17 of the periodic table. All halogens are nonmetals.
Explanation:
here s the answer. Feel free to ask for more chem help
The pKa of formic acid is 3.75. At pH of 5.00, b) [formate] > [formic acid].
Formic acid is a weak acid. Thus, together with its conjugate base (formate) they form a buffer system. We can calculate the pH of a buffer system using Henderson-Hasselbach's equation.
![pH = pKa + log \frac{[formate]}{[formic\ acid]} \\\\5.00 = 3.75 + log \frac{[formate]}{[formic\ acid]}\\\\\frac{[formate]}{[formic\ acid]} = 17.8](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%20%5Cfrac%7B%5Bformate%5D%7D%7B%5Bformic%5C%20acid%5D%7D%20%5C%5C%5C%5C5.00%20%3D%203.75%20%2B%20log%20%5Cfrac%7B%5Bformate%5D%7D%7B%5Bformic%5C%20acid%5D%7D%5C%5C%5C%5C%5Cfrac%7B%5Bformate%5D%7D%7B%5Bformic%5C%20acid%5D%7D%20%20%3D%2017.8)
As expected, at a pH above the pKa, the concentration of formate is higher than that of the formic acid.
The pKa of formic acid is 3.75. At pH of 5.00, b) [formate] > [formic acid].
Learn more: brainly.com/question/22821585