Answer:
3) The calculated density would be high, because the volume would be incorrectly measured low.
Explanation:
Density is defined as mass per unit volume. It means the density is inversely proportional to the volume.
A solid with a hollow center will have high volume due to air inside the hollow area that will lead to low density.
But the error in the calculation of density is that the "density would be high, because the volume would be incorrectly measured low."
Hence, the correct answer is "3)"
Answer:
The most likely outcome is that carrier protein dysfunction will increase the gradient which will lead to disruption of cellular metabolism.
Answer:
Explanation:
Molar mass of As2S3= {75(2) + 32(3)}
= 150 + 96 = 246g/mol
Amount = 3.25mole
And
Amount = mass/ molar mass
mass = amount × molar mass
Mass = 3.25 × 246
mass = 799.5g
For us to accurately determine what compound
this is, additional info must be given. However I can suggest two compounds
which have molecular mass of about 30.07 g/mol.
1. It could be NO or nitric oxide.
The molecular mass is 16 + 14= 30 g/mol
But if we search the exact weight, it is 30.01 g/mol
2. It could also be (CH3)2 or ethane.
The molecular mass is 2*12+ 6*1= 30 g/mol
But if we search the exact weight, it
is 30.07 g/mol.
<span>So we could say it more likely to to be (CH3)2 </span>
The molar mass of a, b and c at STP is calculated as below
At STP T is always= 273 Kelvin and ,P= 1.0 atm
by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation
that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula
that is molar mass = (mass x RT)/ PV
density is always = mass/volume
therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K
the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol
the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol
the molar mass of c
=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol
therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol