An object is thrown with velocity 7.1 m s-1 vertically upwards on the Moon. The

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.150-T magnetic field near the center o

Kamila [148]

Answer:

I = 21.94 A

Explanation:

Given that

B= 0.15 T

Number of turns N= 3100

Length L = 57 cm

Diameter ,d= 7 cm

We know that magnetic field in the solenoid given as

$B=\dfrac{\mu_0IN}{L}$

$I=\dfrac{BL}{\mu_0N}$

Now by putting the values

$I=\dfrac{0.15\times 0.57}{4\pi \times 10^{-7}\times 3100}$

I = 21.94 A

Therefore current need to produce 0.15 T magnetic filed is 21.94 A.

3 0

3 years ago

Consider an ideal gas-turbine cycle with two stages of compression and two stages of expansion. The pressure ratio across each s

kari74 [83]

Answer:

Please see attached

Explanation:

Please see attached

4 0

4 years ago

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WILL GIVE BRAINLIST

marshall27 [118]

Answer:

The Graph Shows World Disasters.

Answer Pt.2:

As we all can see the tornado's Have the highest ratings of natural disasters, Hurricane's happen the next most, Landslide's happen less often, Wildfires also happen less often whereas Earthquakes nearly never happen, they are very rare to the world.

3 0

2 years ago

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A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for

nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block ( $W$ ), measured in newtons, is:

$W = m\cdot g$ (1)

Where:

$m$ - Mass of the block of ice, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 14\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the magnitudes of the weight and normal force of the block of ice are, respectively:

$N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$N = W = 137.298\,N$

And the pull force is:

$F_{pull} = 98\,N$

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

$m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}$ (2)